Here, $\rho$ is the resistance at temperature ($T$) and ($R$) is the resistance at a given temperature. Also, will the value of $α$ become negative if the resistor is cooled?

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What is $RT$ in this formula? - is it a single quantity or product of resistance and temperature (and then why $T(T)$???). – Roger V. Jul 31 '20 at 18:54
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somebody edited this sorry, I just meant R as a function of T – Atharv Kapila Jul 31 '20 at 18:57
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Assume R as resistivity after increased temperature. – Atharv Kapila Jul 31 '20 at 18:58
1 Answers
The equation is just a generalization of an experimental fact that resistance is weakly dependent on temperature. Assuming that $R(T)$ is an unknown function, we can expand $$R(T)\approx R(T_0) + R'(T_0)(T-T_0) + \mathcal{O}\left(\frac{1}{2}R''(T_0)(T-T_0)^2\right).$$ The last term is known experimentally to be small for most materials, which is why a good rule to use in not to extreme conditions is $$ R(T)\approx R(T_0) + R'(T_0)(T-T_0) = R(T_0)\left[1 + \frac{R'(T_0)}{R(T_0)}(T-T_0)\right],$$ we can now define $\rho = R(T_0)$ and $\alpha =\frac{R'(T_0)}{R(T_0)}$ recovering the formula $$R(T) = \rho\left[1+\alpha(T-T_0)\right].$$
Update
This is just one example of many empirical laws which are grounded in observations, but do not really have rigid status of the laws if physics. Most of them are justifiable to a good accuracy in linear regime.
To add more such examples:
- Ohm's law
- Relation $\mathbf{D}=\epsilon\mathbf{E}$
- Relation between the resistance and the cross-section and length of the wire: $R=\rho l/S$
The first two break already for non-linear macroscopic materials, and all three fail at nanoscale and/or in quantum regime.
An interesting counter example is the *laws of thermodynamics, which, although approximate, hold to a very high accuracy, determined by the number of molecules.

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Oh, so it's all about a mathematical expansion and all this time I thought it was supposed to be profoundly conceptual....cool. Thank You. – Atharv Kapila Jul 31 '20 at 19:54
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1@AtharvKapila Well there is a concept, the one that the resistivity is temperature dependent. How does rho depends on T is material specific and there are a lot of different possibilities, and we have found the relationship to good accuracy for many materials. – untreated_paramediensis_karnik Jul 31 '20 at 20:20
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2The point Vadim makes is that, regardless of rho vs T curve, it is always possible to find a small temperature region around T_0 where rho is roughly linear in T. Of course this does not apply near a superconducting critical temperature in a SC material. – untreated_paramediensis_karnik Jul 31 '20 at 20:22
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I added some material to address several points raised in the comments. – Roger V. Aug 01 '20 at 06:15