What do you then mean by constructing a sphere of circumferential radius $r$ centered on the black hole? Is that sphere a 2D surface?
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-1. Not clear what you are asking. – sammy gerbil Feb 16 '17 at 18:08
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This is as discussed in my answer to your previous question: Angular coordinates are unaffected?
The phrase circumferential radius means the radius you get by dividing the circumference of the sphere by $2\pi$ i.e. it is the Schwarzschild $r$ coordinate of the sphere.
The sphere is indeed a two dimensional manifold. That is the $r$ coordinate is fixed and the $t$ coordinate is ignored so points lying in the sphere can be labelled using just the $\theta$ and $\phi$ coordinates.

John Rennie
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