Is spacetime simply connected?

Question

As I've stated in a prior question of mine, I am a mathematician with very little knowledge of Physics, and I ask here things I'm curious about/things that will help me learn.

This falls into the category of things I'm curious about. Have people considered whether spacetime is simply connected? Similarly, one can ask if it contractible, what its Betti numbers are, its Euler characteristic and so forth. What would be the physical significance of it being non-simply-connected?

I do not dare tackle this, but would guess that the four dimensional space is not, since it is divided into space like and time like regions and the twain shall never meet. Then there are all those folded spaces in string theories, Calabi Yao manifolds with lots of holes. We are certainly aiming at non-simply-connected spaces if we include them in space. — anna v, Jul 08 '11 at 05:01
Possibly related: http://physics.stackexchange.com/q/1787/2451 — Qmechanic, Jul 08 '11 at 05:21
Anna V, the first part of your comment indicated that your talking more about causally connected, which isn't really pertinent when discussing global topological structures. — Benjamin Horowitz, Jul 08 '11 at 05:34
Two slightly related facts since you mentioned "Euler characteristic and so forth" (but with little bearing on the question in the title): 1. Sometimes the space-time manifold is assumed to be spin. (For example, this fact is used in Witten's proof of the positive mass theorem.) This requires the vanishing of the second Stiefel-Whitney class, which does tell you something about the topology. — Willie Wong, Jul 08 '11 at 11:00
There are some constraints on the topology coming from the interplay of topology and differential geometry (think Gauss-Bonnet theorem) but it's morally fine to say that GR does not enforce a topology. I believe it's possible to construct spaces satisfying Einstein equations with more or less any homotopy type you want. — Marek, Jul 08 '11 at 12:01
@WillieWong related to your comment is the fact that all 4-manifolds carry a spinc structure https://math.berkeley.edu › spinPDF Web results ALL 4-MANIFOLDS HAVE SPINc STRUCTURES - Berkeley Math — R. Rankin, Nov 12 '21 at 18:27
@AnnaV: Minkowski space is divided into spacelike and timelike regions, but it is simply conndcted. — WillO, May 15 '22 at 23:58

score 10 · Accepted Answer · edited Feb 02 '24 at 06:52

10

I suppose there are many aspects to look at this from, anna v mentioned how Calabi-Yau manifolds in string theory (might?) have lots of holes, I'll approach the question from a purely General Relativity perspective as far as global topology.

Solutions in the Einstein Equations themselves do not reveal anything about global topology except in very specific cases (most notably in 2 (spatial dimensions) + 1 (temporal dimension) where the theory becomes completely topological). A metric by itself doesn't necessarily place limits on the topology of a manifold.

Beyond this, there is one theorem of general relativity, called the Topological Censorship Hypothesis that essentially states that any topological deviation from simply connected will quickly collapse, resulting in a simply connected surface. This work assumes an asymptotically flat space-time, which is generally the accepted model (as shown by supernova redshift research and things of that nature).

Another aspect of this question is the universe is usually considered homogenous and isotropic in all directions, topological defects would mean this wouldn't be true. Although that really isn't a convincing answer per say...

edited Feb 02 '24 at 06:52

Kasiéobì ùdumágà

391

answered Jul 08 '11 at 05:32

Benjamin Horowitz

4,041

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Calabi-Yau manifolds usually have "higher-dimensional" holes (i.e. the ones that are detected by higher homotopy groups but not by the fundamental group). In fact, for any Calabi-Yau manifold there is a finite cover that is a product of a torus and a simply-connected Calabi-Yau manifold. – Marek Jul 08 '11 at 11:52
What about eternal string singularities? BTW, it seems, the cited paper only prevent to “probe topology” and even in such a case may have some lacuna in the proof. – Alex 'qubeat' Jul 08 '11 at 18:02
I am not familiar with eternal string singularities, are there any resources you know about them? – Benjamin Horowitz Jul 08 '11 at 18:31
It is something like that – Alex 'qubeat' Jul 08 '11 at 18:36
LoL… the paper requires a conformal completion of the spacetime with both future and past parts homeomorphic to S² × ℝ. It certainly is not so for the past of a universe formed from cosmological singularity (the starting point of Big Bang). – Incnis Mrsi Aug 22 '14 at 14:25
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"This work assumes an asymptotically flat space-time, which is generally the accepted model (as shown by supernova redshift research and things of that nature)." The universe isn't asymptotic flat because it's homogeneous at cosmic scales, so there's no direction of space in which you can move that will make the universe tend towards Minkowski. If you include taking the far future limit of the universe in your definition of asymptotic, then the universe is asymptotically de Sitter, due to the cosmological constant dominating the universe in the far future. – Totofofo Jan 31 '19 at 11:19

score 8 · Answer 2 · edited May 15 '22 at 20:26

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Benjamin Horowitz's answer covered a lot of the key points, but it's worth adding that the question of the topology of the universe has been investigated by astrophysical observations. If the universe is multiply connected, and if the length scale is shorter than the horizon scale, then we should be able to see evidence of it.

To take a simple example, imagine that the universe is geometrically flat but has the geometry of a 3-torus. Specifically, take a cubical volume, and identify opposite faces, so that if you "leave" the cube through one face you reenter through the opposite face. If the length of an edge of the cube is sufficiently small, then you could see multiple copies of any given object. Of course, if the length is much larger than the horizon, then there's no way to tell the difference between this model and one in which space is infinite.

The best way to test these models is the "circles in the sky" technique, in which you look for correlated circles in different directions in maps of the microwave background radiation. The result is negative: we don't live in a multiply-connected universe with a sufficiently short length scale to be observable.

edited May 15 '22 at 20:26

Urb

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answered Jul 08 '11 at 20:41

Ted Bunn

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Recently preprint appears there also the WMAP data is used, but with claim about possibility of multiply-connected Universe with spatial topology $\mathbb T^2 \times \mathbb R$. It seems not published in a journal yet, but the idea already reproduced in Wikipedia. – Alex 'qubeat' Jul 09 '11 at 16:08
Thanks for the reference. I'd missed that. As I understand it from a quick glance, the idea here is to look at the case where the fundamental cell size is larger than the horizon (so that the circles-in-the-sky technique doesn't work) but not too much larger (or else there'd be no observable effects at all). This is in principle a sensible thing to do, but in this sort of analysis the details matter a lot, and I haven't looked carefully enough to have a sensible opinion about the details. – Ted Bunn Jul 11 '11 at 14:02
@TedBunn your example of the three torus is misleading I believe. One can easily have a non-simply connected space (say a wormhole connecting two regions) and yet still have a simply connected space-time. A simple low dimensional example of this is a circle (non simply connected, which bounds a two disk (simply connected). – R. Rankin Nov 12 '21 at 18:39

Is spacetime simply connected?

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