Bell-type experiments look at the violation of this inequality: $|S|\leq 2$.
where $S=E(a,b)-E(a,b')+E(a',b)+E(a',b')$ and $E$ is the correlation function.
Mathematically, the maximal violation of the inequality is reached when $|S|=4$ (because the bounds of $\cos \theta_{ab}$ are $\pm 1$).
However, wherever I look in the literature it says that experimentally, quantum states produce a violation up to $|S|\leq 2\sqrt{2}$. That is Tsirelson's bound.
The detector settings are always given in intervals of $\frac{\pi}{8}$ radians. A very common set-up in degrees is: $a = 0$, $a' = 45$, $b = 22.5$, $b' = −22.5$.
They seem to take it for granted that this is THE configuration for maximal violation, without an explanation (I think I'm missing something).
Why can't the mathematical maximum be achieved experimentally?
Thanks in advance! :)
Could you please elaborate? And perhaps shed light on that justification? Thanks!
– user3625380 Sep 08 '14 at 14:31