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Can we find at any level, molecules, atoms, particles etc., a perfect elastic collision? If not, what is second best?

EDIT: At macroscopic level what is the most elastic material and the highest CoR recorded? Do you know of a record of a longest bouncing ball on the floor?

bobie
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  • You really shouldn't edit your question to invalidate an existing answer. – dmckee --- ex-moderator kitten Oct 17 '14 at 15:55
  • @dmckee You can see from the time that I was editing my post when Floris answered. The edit does not invalidate the answer, just adds a request about the macroscopic world. Floris may easily update the answer. If he can't, I'll delete the edit and ask another separate question – bobie Oct 17 '14 at 15:59
  • Take two elastic bands and two people and put one of each at the opposite ends of a room. Then get the people to fire the elastic bands at each other at the same time. If the bands smack into each other in mid air, that's what I'd call a perfect elastic collision. :-P – Jim Oct 17 '14 at 18:46

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Let's turn this around. In an inelastic collision, some of the energy, instead of remaining with the center of mass of the objects colliding, is dissipated as heat - an increase in the random motion of the atoms and molecules of the objects colliding.

At the (sub) atomic level, the two particles involved in a simple collision are the same two objects that can "heat up" and carry away the thermal energy. But since their motion is the motion of the center of mass, their collision is by definition elastic.

Now if the collision results in a rearranging of electrons in their orbitals, that argument may not hold: kinetic energy would be converted to a different type of energy. But that cannot happen at the level of subatomic particles (to the best of my knowledge), except at very high energies.

So I would say - for most elementary particles, at low energies, a large fraction of those collisions will be elastic. Note - I did not say all, since there is a probability of some excitation; but I think that a majority of these collisions would be perfectly elastic.

As for the updated question and the "search for the superball": this is tricky, because it takes two to tango in collisions (forgive the mixed metaphor). It's not enough to have a "super ball", you need a "super surface" too. An example of the importance of the surface characteristics is given in "The Effect of the Width of an Aluminum Plate on a Bouncing Steel Ball" - a description of experiments that demonstrate how the coefficient of restitution is a function of the distance from the point of impact to a clamp. A graph from this paper:

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shows that just changing the geometry of the clamps holding the plate changes the coefficient of restitution by a significant amount (when the pressure wave from the impact has time to travel to the clamping point and back, more energy is returned to the ball - the plate undergoes less deflection and thus less loss). Unfortunately I have been able to find very little "good" scientific data on coefficients of restitution. It seems that among sports equipment, golf balls are the best (0.83); superballs (polybutdiene) can reach values of up to 0.90 - but their COR is highly temperature dependent.

You might find this earlier answer I wrote on the subject of bouncing balls interesting in this context - it describes some of the macroscopic factors that influence the observed coefficient of restitution for macroscopic objects.

I suspect that a diamond-on-diamond collision might result in higher COR than even a superball - because the greater the hardness, the smaller the contact area and thus the less friction-related losses. The other thing you can look for in your search for high COR collisions is sound attenuation, which would be an indication of losses (hysteresis) in the material during a pressure cycle. The less sound attenuation, the better the bounce.

Floris
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    You do need to be careful here in the sense that mesons and baryons have substructure and can be excited. Now we usually write this as having a "different" species of particle in the final state, but still. All that you say is true for fundamental particle and for all particles at modest energies (because the excitation energies of hadrons are a significant fraction of their mass). – dmckee --- ex-moderator kitten Oct 17 '14 at 14:59
  • @dmckee - you are right, but I didn't want to go into that; that's why I explicitly said "at low energies". Of course the question was edited after I answered it, and now it seems that the search for the ultimate superball is the real question... – Floris Oct 17 '14 at 15:05