Given that the eigenvalues of a Hamiltonian operator $H$ are bounded below, will a Hermitian operator $T$ exist such that $[T, H] = i\hbar{\bf 1}$ identity operator?
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See Pauli's theorem. Possible duplicates: http://physics.stackexchange.com/q/6584/2451 , http://physics.stackexchange.com/q/34243/2451 , http://physics.stackexchange.com/q/96251/2451 and links therein. – Qmechanic Nov 16 '14 at 00:04
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I proceeded like this: let T be a hermitian operator satisfying the above condition.Let |phi0> be a a eigen ket of the H operator having the least eigen value E0.applying the commutator on both the eigen ket I am getting 1=0 or something like that.where I am going wrong? – Anupam Ah Nov 16 '14 at 07:45