The task goes as following: Calculate the amount of charge $Q$ of a unevenly charged semicircular ring with radiuses $a$ and $b$ if $\eta=\eta_0\sin\phi, 0<\phi<\pi$.
I started off by calculating the infinitesimally small surface $dS$ charged with infinitesimally small charge $dQ$.In this case that surface would be difference between two circular snippets.
$dS=\frac{b^2\cdot\pi\cdot d\phi}{360°} - \frac{a^2\cdot\pi\cdot d\phi}{360°}$
$dS=(b^2-a^2)\frac{\pi\cdot d \phi}{360°}$
and the very next step in the textbook solution is: $dS=(b^2-a^2)\frac{d \phi}{2}$
How did $\pi$ switch from being $3.14$ (coming from $S_l=\frac{r^2\pi \cdot \alpha}{360°}$) to $180°$ (because $\frac{\pi}{360°}$ became $\frac{1}{2}$ in the next step)?
After this I continue with the integration $Q=\int_0^{\pi}\eta_0 \cdot \sin \phi \cdot (b^2-a^2) \frac{d\phi}{2})$ and so on, but the step mentioned above is not clear to me at all.