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It seems that an equation factor must be “squared” as a convenient approximation to balance out some other series of factors invisibly . Might $E=mc^{1.95}$ work as well as $E=mc^2$? Might $A^2+B^2=C^2$ also work if all the factors used the same but different power and be even more accurate? Does anyone know of such a triangle that the current formula comes out to an even number.

Kyle Kanos
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user43769
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