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The D2 line of $^{87}\mathrm{Rb}$ is the transition between the $5^2\mathrm P_{3/2}$ and the $5^2\mathrm S_{1/2}$ states. Its linewidth $\Gamma$ is always quoted to be $\sim 6\ \mathrm{MHz}$.

But both states have hyperfine splittings.

The transition now is between each (allowed) pair of hyperfine states: how do we calculate the linewidth of each of these transitions?

Data sheet for rubidium-87 here.

Urb
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SuperCiocia
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  • To my knowledge very few linewidths (or energy levels for that matter) in data sheets are calculated; they're typically taken directly from experiment. The question is therefore not particularly clear - what calculation are you referring to? – Emilio Pisanty Mar 24 '16 at 19:04
  • Sorry for the delay. I mean, each mF state in the manifold of Rb and K have the same linewidth. Why? – SuperCiocia Jun 30 '16 at 15:31
  • Apparently there is a theorem that justifies it. – SuperCiocia Jun 30 '16 at 15:31

1 Answers1

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This is duplicate of the following:

Is this answered sufficiently for you there?

kai90
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