Related note:
Fission isn't exactly turning matter into energy. It just releases the binding energy of the nucleus. This binding energy is part of the measured mass pf the nucleus, but if you want to separate "matter" and "energy" (not really possible), then it counts as energy.
$\newcommand{\a}[3]{\mathrm{^{#1}_{#2}#3}}$
$$\a{235}{92}{U}+\a10n\to\a{236}{92}{U}^*\to\a{144}{56}{Ba}+\a{89}{36}{Kr}+3\a10n+|\Delta H|\approx177\:\rm{MeV}$$
Note that initially, we have 93 protons and 142 neutrons; and in the end this number does not change. From this POV, where particles count as "mass", we can say that no mass was created or destroyed, and the nuclear binding energy was released.
Why do we call this a conversion from mass to energy if its just a converseion of types of energy? Well, that's because mass is energy.
The fact is, if you "weighed" $\a{235}{92}{U}+\a10n$, it would weigh more than $\a{144}{56}{Ba}+\a{89}{36}{Kr}+3\a10n$. Actually, $\a{235}{92}{U}$ weighs less than $92\a11p+141\a10n$. That's because the binding energy of the nucleus is "negative" energy, and thus "annihilates" some mass (since mass is energy). It turns out that due to this, the fission products are lighter than the reactants, even if the number of nucleons is the same. And this loss of "mass" is converted into energy.
So really, there's a bit of fuzziness on the border of "energy" and "mass". Anything with an energy density will have extra mass, and you won't be able to tell the difference between a body with mass $m$ and a body with mass $m-\frac{U}{c^2}$ and internal energy $U$.