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When considering buoyancy in a gaseous medium, if the gas has the same density everywhere, is it possible for buoyancy to exist? Or the gas need to be more dense in the lower layers for the buoyancy to exist? In liquid, there is no density difference, but there is pressure difference. So in a gas, there must be also pressure difference for the buoyancy to exist, so does that mean that there must be a density difference due to gravity?

ergon
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To answer your question you need to consider how the buoyancy effect arises.

It is much easier to consider a particular case rather than a general one.

enter image description here

The left hand diagram shows a cylinder of fluid (red) in equilibrium with the rest of the same fluid (blue).

You can now consider the red cylinder of fluid as a system.

That red fluid has two sets of forces acting on it.
The attractive force due to the gravitational attraction of the Earth $W$ downwards and the forces due to the blue fluid.

If the cylinder is vertical then the net horizontal force on the red fluid due to the blue fluid is zero.
The net force up due to the blue fluid is $F_B-F_T$ and if the area of the ends of the cylinder is $A$ then this force is $(P_B -P_T)A$

Since the red fluid is in equilibrium $W= (P_B -P_T)A$

This tells you that the buoyancy effect (weight of fluid displaced) is due to the difference in pressure between the bottom and top of the cylinder.
That pressure difference will depend on the distance between the top and bottom of the cylinder, the density of the blue fluid and gravitational field strength.

A change in density of the blue fluid with height will obviously affect the pressure difference but if that change in density is relatively small which is often the case, it is the vertical height which is the more important factor.

Farcher
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  • If there an equation for the buoyancy in gas? or in atmosphere? – ergon Mar 14 '16 at 10:46
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    It will the same as for any fluid. The "upthrust" is equal to the weight of the fluid displaced". To work out the weight you need to split the volume into infinitesimal elements of volume $A dh$ and for each of them work out $\rho(h) g(h) A dh"$ and then sum the lot. $\rho(h)$ and $g(h)$ is how the density and gravitational field strength vary with height $h$. In lots of cases if the density and gravitational field strength are assumed to be constant and then the upthrust is $\rho g V$ where $V$ is the volume of the fluid displaced. – Farcher Mar 14 '16 at 10:57
  • ok but my question is basically simpler: we have a gas in a box in specific pressure, is there buoyancy in that fluid? I suppose yes. Now my question is, we take the same box in space, with zero gravity. The gas will be inside the box in the same pressure, will there be buoyancy inside that gas? if we put an object inside that gas? – ergon Mar 14 '16 at 14:51
  • The buoyancy effect only is there if there is gravity (or if the box is accelerating). The acceleration example is the basis of operation of the centrifuge where in effect you increase the local value of $g$. – Farcher Mar 14 '16 at 15:55
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    OK. Now if we have gravity, don't we ALWAYS have larger pressure at the lower layers of a gas inside a box under specific pressure? – ergon Mar 14 '16 at 20:12
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    I think so. Do you have an example when that does not happen? – Farcher Mar 14 '16 at 20:49
  • An interesting demo to help convince you of these principles. Imagine helium balloons in a car. You accelerate. Are the balloons forced to the back of the car like your body? No! The acceleration results in a horizontal buoyant force and the balloons move forward obstructing your view. So be careful if you try this! – docscience Mar 30 '16 at 19:16
  • docscience that is not buoyancy, that is drag – ergon Apr 10 '16 at 17:26