Pascal's law states that when there is an increase in pressure at any point in a confined fluid, there is an equal increase at every other point in the container.
To explain this, the hydraulic jack is a better example. Car jack works on mechanical forces. A mechanical jack employs a screw thread for lifting heavy equipment. But hydraulic jacks use force generated from pressure. It's working can be explained using Pascal's law. A hydraulic jack contains two cylinders (one having larger area and the other smaller) connected each other and inside them an in-compressible liquid. Once a force is applied to the small cylinder, a pressure develops on the surface of the cylinder. According to Pascal's law, the same pressure will be transmitted to the entire parts of the fluid. So at the other cylinder the same pressure appears. At the second cylinder, the surface area is large. Since $\displaystyle{pressure=\frac{force}{area}}$ the force acting in the upward direction on the second surface will be larger. So you apply a small force on the cylinder with smaller surface area and you will get a much larger force on the second surface having larger surface area.
As a quantitative example, suppose I have two cylinders $C_1$ and $C_2$. The surface areas of $C_1$ and $C_2$ are denoted as $S_1$ and $S_2$. Let $S_1=1 m^2$ and $S_2=100 m^2$. An in-compressible liquid is present in the cylinders and both are connected. You apply a force of about $600N$ (an average man's weight; suppose you are standing on the first cylinder's surface) on $S_1$. Then it will generate a pressure of $600N/m^2$. By Pascal's law, the same pressure appears on $S_2$. then the force appearing on $S_2$ will be $60000 N$!!!. Impressive, isn't it? That's the weight of 4 cars. you just lifted 4 cars just with your weight. No sweat.
The additional force came from no where. the pressure just remains the same as the liquid is in-compressible. The effect of force comes different when you apply different surface areas connected by the liquid. If you apply two same surface areas, there is no additional force. Here the surface area has great relevance. You cannot just avoid it and think in terms of force alone.