Suppose to be in an arbitrary gravitational field and you are moving in it arbitrarily with a clock in your hand. In this general situation I ask: if I read the positions of the hands of the clock, what am I really measuring the proper time or a simple coordinate?
Asked
Active
Viewed 121 times
1
-
A clock in your hand measures time. What the coordinates in general relativity mean is totally up to your choice of coordinates. – CuriousOne May 31 '16 at 20:45
-
4Possible duplicate of Why do clocks measure arc-length? – ACuriousMind May 31 '16 at 20:47
1 Answers
1
You are reading the proper time (which is, of course, the value of one of many possible coordinates).
-
@Yildiz Indeed they will: given the curve you follow in spacetime, all observers agree on its length. – May 31 '16 at 20:52
-
Suppose there is a strong gravitational field between you and your clock and that it varies in such a way that the light that arrives from the hands of the clock changes so you see the hands going in an irregular, non periodic way, as a normal clock shouldn't do: how is it possible that everyone will agree on this measure of "time" if this is a proper time and so a scalar? – Yildiz May 31 '16 at 21:08
-
@Yildiz: Periodicity is not a necessary requirement for a clock, only monotonicity is. – CuriousOne May 31 '16 at 21:19
-
I want to be precise about this: suppose to be in an arbitrary gravitational field, what is your operative definition of "time"? – Yildiz May 31 '16 at 21:26
-
@Yildiz The proper time along a (suitably smooth) timelike curve is simply its length, which, if you know the metric, is $\int\sqrt{\pm g(\vec{\lambda}(t), \vec{\lambda}(t))},dt$ where $t$ parameterises the curve, and$\vec{\lambda}(t)$ is the tangent vector to the curve at $t$. – May 31 '16 at 21:32
-
I asked how to measure, in a real and concrete way, time in general relativity using a clock: I want an operative definition that take in consideration also the presence of strong gravitational fields between me and clock, able to deviate the light that i see coming from the hands. If is not possible to give this definition how is it possible to say that the proper time is the one "measured" if i don' t have a standard definition on how to compute this measure? – Yildiz Jun 01 '16 at 13:16
-