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I'm struggling to understand the argument on p. 13 in Landau and Lifshitz that for a system with $N$ degrees of freedom there must be $2N-1$ integrals of motion.

In particular, I can't understand how this works for a free particle. Clearly, the system is translationally and rotationally invariant. I think that the angular momentum is independent of the linear momentum. So then it seems like there are 6 independent integrals of motion, one for each component of linear momentum, and one for each component of angular momentum. Where does this argument go wrong?

Any help is much appreciated.

Qmechanic
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    Related : "Integrals of Motion" http://physics.stackexchange.com/q/13832 Anode "Integrals of Motion for s Degrees of Freedom" http://physics.stackexchange.com/q/134744 "Constants of motion vs. integrals of motion" http://physics.stackexchange.com/q/55861 – sammy gerbil Jun 12 '16 at 11:51

1 Answers1

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The resolution is that the 3 linear momenta $p_i$ and the 3 angular momenta $L_i$ are not independent integrals of motion. They satisfy a quadratic relation $\vec{p}\cdot \vec{L}=0$. So the 3D free particle has only 5 independent integrals of motion.

Qmechanic
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