I am learing about quantum mechanics, and I am quite unclear about the the role of measurement and the density operator.
Let $\mathcal H$ be a Hilbert space, $\psi(t) \in \mathcal H$, $O$ be a bounded hermitian operator (“observable”) with discrete eigenvalues $o_n$.
Immediately after a measurement at time $t=t_0$ yielding $o_i$, the state will be projected into the Eigenspace of the operator for that corresponding eigenvalue: $$\left\{ \phi: \|\phi\| = 1 \:\wedge\: O\phi = o_i \phi \right\} = \{\phi_{i\lambda}: \lambda \in \{0..d_i\}\}$$ …if $o_i$ is $d_i$-degenerate.
- Is that a correct formulation of “being projected onto the eigenspace”?
Thus, our $\psi' = \sum\limits_{\lambda=0}^{d_i}\langle\psi(t_0),\, \phi_{i\lambda} \rangle$
Is it correct, that for non-degenerate eigenvalues, the resulting state must be pure, since we project only against $\phi_{i0}$ being an eigenstate itself and not a superposition of multiple eigenstates?
What the heck is the density matrix? I often read about it and heard definitions, but what deeply confuses me is that in certain literature, it is not mentioned at all (see an example). What role does it have? Why do we need it? And why don't we, appearently?
This kind of question probably has been asked before, but I hope I could explain specifically what my knowledge base and confusion is. Other questions would mostly assume I understood the density matrix, and others still don't explain why/how quantum mechanics can be done without it, apparently.