When obtaining the equation of a pendulum following classical mechanics (Virtual Work) we state that:
The work is in equilibrium, therefore $\textbf{F} = 0$ and the Virtual Work is
$$\textbf{F} ยท \delta \textbf{r} = 0\tag{1}$$
But, is a pendulum in equilibrium? I mean, the velocity of the pendulum changes with the time, how can we say that the pendulum is in equilibrium?
Often is also used the expression
$$\textbf{F} - m \ddot{\textbf{r}} = 0\tag{2}$$
to express this equilibrium, but it isn't an equilibrium at all, since the only think we do is move to the left the inertial force from the Newton's second equation $\textbf{F} = m \ddot{\textbf{r}}$.
Goldstein sais in his book that equation (2) means: that the particles in the system will be in equilibrium under a force equal to the actual force plus a "reversed effective force" $- m \ddot{\textbf{r}}$.
What does it mean an how applies this to the pendulum?