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For a given set of fast-moving objects in empty space, the maximum mass-energy that can be extracted by using only interactions between objects in the set (e.g., colliding all of them together) is identical to the relativistic mass-energy that an observer would see when residing in the center-of-mass inertial frame for that set. (You can trust me on that or prove it yourself; it's not difficult.)

This is why a proton colliding with earth at $\gamma=10$ velocity does not cause a catastrophic release of ten earth's worth of energy. Since the mass of the proton is entirely negligible in comparison to the earth, the mass-energy available by colliding all objects in the set {earth, proton} is very close to the mass of earth plus ten times the mass of the proton.

Thus for any set of objects that are isolated in space, the center-of-mass inertial frame is the only special relativity frame for which the observed mass-energy of all parts is identical to the available mass-energy. More energy can of course be extracted, but only by bringing in objects that were not in the original set. The center-of-mass inertial frame thus is both "distinguished" and unique with respect to that set of objects (only).

Now here's the fun part: Define the set to include all objects in the universe. Since you have just placed all your eggs in one basket, so to speak, there are no longer any objects to bring in from outside to alter the result, even in principle. Next, calculate for "distinguished" inertial frame for this set. (For a pretty good guess, try the CMB.)

My question is this: Doesn't the above argument imply that under the rules of special relativity the universe really does have a single, unique, and non-trivially distinguished inertial frame, that being its center-of-mass inertial frame?


Addendum 2012-05-30.20:220 EST

Angular momentum

I skipped over angular momentum in defining the set of objects used to define the minimum energy SR frame. Unlike linear momentum, residual angular momentum in a set of object of course cannot be resolved simply by resetting the frame. Always interesting, angular momentum, since if it exists it necessarily "points" to additional matter that exists outside the current set, at least if you believe in absolute universal conservation of it (which I certainly do). Its energy can be quantified locally, though.

"Center of mass" in curved spaces

@LubošMotl and others brought up the excellent point that you can't really do a center of momentum for curved space. If you assume that the curved space can be embedded within a larger Euclidean space (Nash proved that in his last pre-breakdown paper, which was an amazing work), then it's easy to see that the center of mass of the curved piece is not very likely to fall within the piece itself. It's more likely to wind up somewhere "other" than the surface, e.g. for an ordinary balloon it falls at the center of the balloon! So, when I say "center of mass frame," I'm really using a sloppy shorthand for a procedure that would require following along the locally 3D surfaces to construct an overall average. Theorem: For any smooth manifold decorated with components that move locally in accordance to the accepted rules of mass, energy, and momentum conservation, and whose shape can be approximated as being invariant over the time scales considered for those motions, there exists a singular "manifold rest frame" that is motionless with respect both to (a) the overall form of the manifold if it is irregular, and (b) with respect to the SR energy minimum defined for the entire set of components moving within the manifold.

(I am dancing lightly over rotations in 4D; there are two orthogonal ones, makes life interesting. I'm also skipping over the issue of the two different forms of 4D holes, the equivalents of 1-spheres (rings) and of 2-spheres (balloons), on the assumption that such topologies are unlikely for a realistic universe.)

(All dimensional solids n>3 have more than one type of, each hole type having an equivalence to one of a series of lower dimensional spheres from the 1-sphere (ring) to the (m-2)-sphere. That's not counting erasures (m=n), splits (m=n-1), and internal voids (m=0) (Do they address that in string theory? If not, how do they specify or distinguish between the 7 or 8 hole types of the n=9 or n=10 spaces used in M-theory? Ah.. hmm... maybe I should make that into a real question?)

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    You can't use special relativity for the description of the whole Universe. Instead, general relativity is needed and it doesn't preserve the concept of "inertial frames" at all. The only context in which your questions would be meaningful would be "alternative" non-gravitating physics of a Universe in a flat Minkowski spacetime. With a finite average mass density etc., it would be unstable. However, if you also banned a cosmological constant, and it's natural to ban it in special relativity, the positivity of energy would obviously pick a preferred reference frame. – Luboš Motl May 30 '12 at 17:49
  • Does it make physical sense to include objects in your set if they're outside the light cone of the centre of mass? I don't mean that it doesn't, it's just that I get suspicious about concepts that involve the whole of the universe :-) – John Rennie May 30 '12 at 17:53
  • I think you asked it better than I did, so I wouldn't try to close this, but I do still just want to mention that I asked pretty much the same thing here http://physics.stackexchange.com/questions/11633/how-are-the-comoving-coordinates-not-a-prefered-reference-frame – Alan Rominger May 30 '12 at 18:27
  • All, thanks! @LubošMotl, I freely admit to the abrupt generalization have huge holes, e.g., the center of mass of the universe can't even exist in the universe (a fascinating point about which I've had some interesting discussions with friends; my view was that it has to reside way back at the Big Bang). So, yes, but I think (?) I'm shooting more for how the "specialness" of certain frames seems (?) to increase as you broaden your scope. So, if you can bear with me a bit that intentional bit of skipping over, its that unexpected "specialness" that fascinates me. (And there is that CMB...) – Terry Bollinger May 30 '12 at 19:53
  • @JohnRennie, I think it's OK to go outside the light cone as long as the space is reasonably flat (see above comments about the curved case). I could be wrong on that -- it would be fascinating to be wrong on that! -- but if nothing else, ordinary mass-energy conservation across space would seem to argue for "future reconciliation" being sufficient. – Terry Bollinger May 30 '12 at 19:56
  • @AlanSE, cool, thanks! And thanks also letting this one play out a bit. I looked for predecessors as thoroughly as I could -- was hoping for some in fact -- but came up dry for he keywords I was using. I either just didn't see yours or got hit by having a different set of terms for framing (heh, "framing") the issue. – Terry Bollinger May 30 '12 at 19:59
  • I think you mean centre of momentum frame – Larry Harson May 30 '12 at 21:38
  • @LarryHarson, interesting point to bring up! Imagine the reverse situation: Start with all of the mass at roughly a single point, fully isolated from any external masses or significant fields. The mass then blows up into pieces of many sizes and many velocities. For variety, each piece may also blow up in the same way, and so on down the line. Where is the center of momentum, that is, the point at which all linear and angular momenta add up to zero? Back at the point-like origin. Where is the center of mass? Also back at the point-like origin! They are the same thing for a truly closed system. – Terry Bollinger May 31 '12 at 00:18
  • I think we are in agreement? If I forgot to append "frame" after "center of mass" it was inadvertent, since my intent was to invoke the frame from which an observer would see a point representing the center of mass appears as motionless. – Terry Bollinger May 31 '12 at 13:50
  • Sorry, I said center of mass when I should have center of momentum. Here's the comment as it should have been written: "Center of mass defines a single point, is frame dependent and therefore not used, but the center of momentum frame is where all the momentum sum to zero, and defines a frame rather than a point that everyone agrees upon which is ok. Centre-of-mass frame is commonly misused to mean centre of momentum and only makes sense for v<<c in Newtonian mechanics. – Larry Harson May 31 '12 at 15:44
  • Thanks, I was getting a bit bewildered there!... point well taken, especially regarding v<<c... it's the relativistic mass issue, yes? I was using center of mass frame as derived after you have already become classically close to the frame in question, which is... messy at best? – Terry Bollinger Jun 01 '12 at 10:01

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It's true that the CM frame of a set of objects is distinguished with respect to that set of objects. But that doesn't qualify it as a preferred rest frame, as far as special (or, locally, general) relativity is concerned. After all, the laws of physics will still hold just as well whether you're in the CM frame of any particular set of objects or not. So there's no contradiction with relativity there.

This is kind of like a case of spontaneous symmetry breaking, in fact. The theory itself works the same no matter which reference frame you're in, but the system that the theory applies to does look different from different reference frames. So the system "spontaneously" selects a particular "natural" reference frame, the CM frame, for you.

David Z
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  • One thing I like about this question is what you said: There's nothing about it that violates SR, since if you find more mass outside of your set, you simply reset the CM and it tells you how much more mass-energy is available. You get your distinguished frame for what you know, but also get to keep SR intact -- a sort of "have your cake and eat it too" situation. Nice point about symmetry breaking, I hadn't thought of that. I'll wait a bit first for anyone else to jump in. – Terry Bollinger May 30 '12 at 22:31