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Can someone please explain why the graph is linear from the start to the surface? enter image description here

Qmechanic
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Anonymous
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1 Answers1

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From Gauss's law for gravity we have:

$$\frac{1}{4\pi}\int\mathbf{g}\cdot d\mathbf{a}=-G M_{enc}$$

$$\frac1{4\pi}g(r)\cdot4\pi r^2=-G\rho\cdot\frac 43\pi r^3$$

$$\mathbf{g}(r)=-\frac43\pi\rho G r \mathbf{\hat r}$$

AHB
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