Physical interpretation of Glauber states

Asked Jan 17 '17 at 19:52

Active Jan 17 '17 at 19:52

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The definition of a Glauber, or coherent, state is

$$a|\alpha\rangle = \alpha|\alpha\rangle.$$

Why is this a useful definition? Grynberg's Quantum Optics book simply says "a quasi-classical state $|\alpha\rangle$ is the eigenstate of the annihilation operator $a$.

asked Jan 17 '17 at 19:52

NoethersOneRing

3

relevant: http://physics.stackexchange.com/questions/10391 http://physics.stackexchange.com/questions/90034 http://physics.stackexchange.com/questions/119104 http://physics.stackexchange.com/questions/89018 – AccidentalFourierTransform Jan 17 '17 at 19:57
Ah darn. I was searching for Glauber states. Thank you! – NoethersOneRing Jan 17 '17 at 19:58
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Possible duplicate of What exactly is a coherent state and why is it interesting? – Emilio Pisanty Jul 16 '18 at 11:54

Physical interpretation of Glauber states

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