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This is an attempt to ask separately about aspects of my previous question, which was closed as too broad. Note that I strongly prefer results that are or can be made mathematically completely rigorous. This question is essentially the same as proof of radius of convergence of perturbation series in quantum electrodynamics zero (2)

Related questions include How can an asymptotic expansion give an extremely accurate predication, as in QED? and Asymptoticity of Pertubative Expansion of QFT, which has a nice reference to some lecture notes on the connection of perturbative and non-perturbative aspects of QFT.

As far as I know, the free quantum theories for both the Dirac field as well as the Photon field on Minkowski space are well defined, that is: One has a Hilbert space (the fermionic and bosonic Fock spaces respectively) and a self-adjoint (in the precise mathematical sense of the term) Hamiltonian operator for the free evolution. In addition one has a unitary representation of the full (disconnected) Poincaré group (correct me if I'm wrong, precision is a big issue for me here). This allows one to treat the free theories just as nonrelativistic quantum theories. In some inertial frame of reference one can specify an initial state, specifying a field configuration. One would then be able to calculate the state at a later time (in that frame), or as it would be seen from a different reference frame, without the need for any perturbation theory. I think one can also meaningfully answer questions as "what is the probability of detecting exactly one photon within a given spacetime region". One would have to work in "position space" but it seems like a meaningfull question. In principle using suitable numerics and arbitrary amounts of computation time, all such well-defined problems can be given arbitrarily precise answers?!

In the interacting theory (full QED, the two above free theories + minimal coupling), this does not seem to be the case. One does not have a Hilbert space and it goes without saying that there are no well-defined operators to speak of. The theory is "defined perturbatively", where one (after renormalization) only (Correct me, as I assume this claim is wrong) makes predictions for scattering cross sections and decay rates in the form of formal power series (where each term is finite after renormalization) in something somehow related to the fine structure constant. For this I would like to quote part of one answer from (2):

[...] EDIT: Many think the perturbation parameter in QED is α∝$e^2$ , but it is not the case. To obtain a meaningful calculation result, one has not only to perform renormalization, but also fulfill soft diagram summation. The latter is equivalent to taking into account α in another initial approximation. In other words, the meaningful perturbation expansion is different from the Dyson's one and may converge. The subtlety is not immediately visible, but it is implied that each term of Dysons' expansion is different from zero, and it is not so! For example, a Compton scattering amplitude calculated in the first Born approximation (Klein-Nishina) represents an elastic process that never happens in reality and in the theory because soft photon radiation. Only inclusive cross sections are different from zero in QED. The Klein-Nishina formula is multiplied in QED by an elastic form-factor whose first term of the Taylor series is unity, but the rest, after summation, gives zero, like $e^{−x}=1−x+x^2/2−...$ when $x\to \infty$.

My question is:

In the final state of full QED (renormalized etc.), has it been shown rigorously (Dyson's argument is not rigorous!) that the perturbation expansion for physical quantities (for example the magnetic moment of the electron) does not converge? Surely this has been tried. Is it an open problem in 2017? The above answer suggests that the expansion is not in powers of the fine structure constant, which contradicts many other sources. What is the expansion parameter really?

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    You cannot show anything rigorously in QED, because the theory itself is very far from being something mathematically rigorous. – AccidentalFourierTransform Apr 11 '17 at 10:42
  • Seconding the above comment: When you say rigorous, what rigorous framework for QFT are you thinking about? Aside from free field theories and some examples in two and three dimensions, no fully rigorous formulation of a QFT by mathematical standards is known. (Note that one of the millenium problems is essentially exactly about that for the case of QCD/Yang-Mills) – ACuriousMind Apr 11 '17 at 11:06
  • While the "theory" is not rigorous, the perturbation series I'm talking amount are just a bunch of finite coefficients and powers of an expansion parameter, which are perfectly rigorous things. The question is if those numbers can be summed (or rather if it has been proven yet that they can't). That question might be difficult but it is certainly well-posed ?! – Adomas Baliuka Apr 11 '17 at 11:44
  • Note that my excuse for this being essentially a duplicate of the linked question is that I don't understand the quoted part of an answer therein. Note that the analogous question for several (interacting!) 3+1 dim. scalar field theories are answered. See, e.g. results quoted in https://arxiv.org/abs/hep-th/0207046 – Adomas Baliuka Apr 11 '17 at 12:28
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    @AccidentalFourierTransform: If one is happy defining a QFT in the sense of formal power series then this has been done with full mathematical rigor. See this book http://link.springer.com/book/10.1007/3-540-50213-0 So something has been shown rigorously in QED. However, I agree with you that this something is not what one would really like, i.e., a rigorous nonperturbative construction. – Abdelmalek Abdesselam Apr 11 '17 at 12:52
  • @AdomasBaliuka: asking for the series to converge is the wrong thing to ask. The series coefficients do not have to grow like $C^n$ for one to be able to construct the theory rigorously and nonperturbatively. If it grows like $C^n n!$ one can try using Borel summation (even higher powers of the factorial can be managed by Borel-Leroy techniques). In the examples that have been constructed rigorously like $\phi^4$ in 2d and 3d, the series has zero radius of convergence but it has been proven to be Borel summable... – Abdelmalek Abdesselam Apr 11 '17 at 13:00
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    ...See the references in the obituary article for Roland Seneor in http://www.iamp.org/bulletins/old-bulletins/Bulletin-Jul2016-print.pdf – Abdelmalek Abdesselam Apr 11 '17 at 13:01
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    BTW: I don't know about QED in 4d (I don't have the book by Feldman et al. which I recommended to AccidentalFT in front of me), but for $\phi^4$ in 3d the proof of divergence of the perturbation series is here: http://projecteuclid.org/euclid.cmp/1103920746 – Abdelmalek Abdesselam Apr 11 '17 at 13:13
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    A related question: https://physics.stackexchange.com/q/422975/ – maplemaple Dec 19 '18 at 03:48

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