The graviton is in a sense an entangled triplet state of two gauge bosons. The glueball state of two gluons in a triplet state is quantum mechanically the same as a graviton. However, it is not the case a glueball is a graviton. These decay quickly because the color charge internal to the system is very strong. The S-dual of QCD may though have a very weak color charge, which will make the ensuing entangled pair very weakly interacting and stable.
The two considerations, one a gauge transformation defined by the root vectors of a Lie algebra and the other gravitation, are considered with respect to each other. The Riemann curvature with vanishing Ricci curvature is the Weyl tensor. For sourceless region the curvature is purely vacuum and given by the Weyl tensor. Given null vectors $U^\alpha$ the null vector $U^{\alpha\beta}~=~[U^\alpha,~U^\beta]$ is defined. These are eigen-bivectors of the Weyl tensor
$$
\frac{1}{2}{C^{\mu\nu}}_{\alpha\beta}U^{\alpha\beta}~=~\lambda U^{\mu\nu}.
$$
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Consider the metric composed of the null vectors $x_\alpha,~y_\alpha,~z_\alpha$, wuch that $z^\alpha y_\alpha~=$ $x^\alpha y_\alpha~=~-1$ and $\bar y^\alpha y_\alpha~=~1$,
$$
g_{\alpha\beta}~=~x_\alpha z_\beta~+~z_\alpha x_\beta~+~y_\alpha\bar y_\beta~+~\bar y_\alpha y_\beta.
$$
There are then three possible null bivectors
$$
U_{\alpha\beta}~=~-X_{[\alpha}y_{\beta]},~V_{\alpha\beta}~=~z_{[\alpha}y_{\beta]},~W_{\alpha\beta}~=~-y_{[\alpha}\bar y_{\beta]}~-~-X_{[\alpha}y_{\beta]},
$$
so the Weyl tensor is composed as
$$
\begin{align}C_{\alpha\beta\mu\nu}&~=~ \Psi_0U_{\alpha\beta}U_{\mu\nu} \\
&\, \, \, ~+~\Psi_1(U_{\alpha\beta}W_{\mu\nu}~+~W_{\alpha\beta}U_{\mu\nu}) \\
&\, \, \, ~+~\Psi_2(V_{\alpha\beta}U_{\mu\nu}~+~U_{\alpha\beta}V_{\mu\nu}~+~W_{\alpha\beta}W_{\mu\nu}) \\
&\, \, \, ~+~\Psi_3(V_{\alpha\beta}W_{\mu\nu}~+~W_{\alpha\beta}V_{\mu\nu}) \\
&\, \, \, ~+~\Psi_4V_{\alpha\beta}V_{\mu\nu}\end{align},
$$
for $\Psi_i$ Weyl scalars. These define different physics; $\Psi_2$ gives the vacuum around a central source, such as a black hole, $\Psi_4$ are transverse modes and $\Psi_1,~\Psi_3$ are in and out directed longitudinal modes.
Each of the bivectors may be expressed according to a vierbein $U^a~=~E^\alpha u^a_\alpha$, where now the Latin indices refer to spacetime and Greek indices correspond to an internal space given by the root vectors of a Lie algebra. We can then see that $U_{ab}~=$ $2[E^\alpha,~E^\beta]U_beta^{[b}U_\alpha^{a]}$. The Weyl tensor is then
$$
C^{abcd}~=~ 2\Psi_0[E^\alpha,~E^\beta][E^{\alpha'},~E^{\beta'}]U^{ab}_{\alpha\beta}U^{cd}_{\alpha'\beta'}
$$
$$
~+~2\Psi_1[E^\alpha,~E^\beta][E^{\alpha'},~E^{\beta'}](U^{ab}_{\alpha\beta}W^{cd}_{\alpha'\beta'}~+~W^{ab}_{\alpha\beta}U^{cd}_{\alpha'\beta'})
$$
$$
+~2\Psi_2[E^\alpha,~E^\beta][E^{\alpha'},~E^{\beta'}](V^{ab}_{\alpha\beta}U^{cd}_{\alpha'\beta'}~+~U^{ab}_{\alpha\beta}V^{cd}_{\alpha'\beta'}~+~W^{ab}_{\alpha\beta}W^{cd}_{\alpha'\beta'})
$$
$$
+~2\Psi_3[E^\alpha,~E^\beta][E^{\alpha'},~E^{\beta'}](V^{ab}_{\alpha\beta}W^{cd}_{\alpha'\beta'}~+~W^{ab}_{\alpha\beta}V^{cd}_{\alpha'\beta'})
$$
$$
+~2\Psi_4[E^\alpha,~E^\beta][E^{\alpha'},~E^{\beta'}]V^{ab}_{\alpha\beta}V^{cd}_{\alpha'\beta'}
$$
where the bi-vierbeins $U^{ab}_{\alpha\beta}$ are evidently defined. The nature of the gauge field or gauge-like field associated with these Lie algebraic roots is discussed
in the last section.
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The root vectors $E^\alpha$ obey the commutators
$$
[E^\alpha,~E^\beta]~=~N^{\alpha\beta}H^{\alpha+\beta},
$$
where $H^{\alpha+\beta}$ are the weights. With any Lie algebra there are elements that are analogous to $a$ $a^\dagger$ for the harmonic oscillator, which are the standard roots $E^\alpha$ and $a^\dagger a$ that correspond to the weights $H^\alpha$. For the gauge theoretic description of the $\hat C$ operators the result is linear in the weight. For gravitation the operator is quadratic in the weights. The Weyl tensor for type $D$ and $II$ solutions are eigenvaled with $C_{abcd}U^bU^c~=~\lambda U^aU^d$. It is possible to see the Weyl tensor for these eigenvalued Petrov types obeys
$$
C_{abcd}U^bU^c~=~\lambda E_\alpha E_\delta U^\alpha_a U^\delta_d.
$$
Consequently the Weyl tensor for these eigenvalued Petrov types obeys
$$
C_{abcd}U^bU^c~=~N_{\alpha\beta}N_{\gamma+\delta}H_{\alpha+\beta}H_{\gamma+\delta}U^\alpha_a U^\beta_bU^\gamma_cU^\delta_dU^bU^c~
$$
$$
=~N_{\alpha\beta}N_{\gamma+\delta}H_{\alpha+\beta}H_{\gamma+\delta}E^\beta E^\gamma U^\alpha_a U^\delta_d~=~\lambda E_\alpha E_\delta U^\alpha_a U^\delta_d.
$$
The commutators of the Lie algebraic roots concern the observables $A_i$ and $B_i$ on either side of the apparatus. In the case of a Lie algebra a gauge transformation, or the introduction of a force, transforms these operators relative to each other. This results then in a modification of the Tsirelson bound. Similarly, for gravitation the parallel translation of these operators on either side of the apparatus does the same.
This is a bit formal, We may thought think of the weights as the states of gluons. These are formed from the commutator of the root vectors. The product of weights sum over the internal index of the Lie algebra and form a Weyl tensor. In this way we have derived some aspects of a graviton from the group representation of a gauge particle. In particular the graviton is a product of the gauge particle.
