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If I travel almost side by side with light, and my speed is lets say 99% of speed of light..would I see the light going near me at the speed of light (i mean as same as when i would not be moving, when i would be stationary) or would i be able to actually see it going besides me?

Qmechanic
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    At all velocities you would still observe light to be going at c. –  Nov 07 '17 at 19:58
  • so i would not be able to "run" away from light? so that instead of 0.5 sec the light reaches me in 0.6sec – Patrik Ponjavić Nov 07 '17 at 20:10
  • Nope, not at all. The speed of light doesn't care about how fast you're going, especially since at all points during your journey you might as well be stationary at instants anyway. Travelling at 0.9999c is only relative to some co-ordinate system, it would be undetectable in your frame of reference. –  Nov 07 '17 at 20:21
  • but the train experimetn where the observer in the trian sees the light which appears infront of him before the light from behind him doesnt mathc up with thi logic odes it? thanks for your time btw – Patrik Ponjavić Nov 07 '17 at 20:29
  • Sorry but I don't understand your phrasing –  Nov 07 '17 at 20:35
  • https://www.youtube.com/watch?v=wteiuxyqtoM in this video the women in the train see the light infront of her sooner than the light behind her.. how? – Patrik Ponjavić Nov 07 '17 at 20:44
  • I think your question is not clear so the answers might be not adressing what you mean. Yes if you escape from light , does not matter at which speed you move, you put space between it and you. It will take longer for the light to reach you. In the ideal case you move at c, the light beamed at your back won't catch you. But it is still going at c. – Alchimista Nov 07 '17 at 21:08
  • If speed of light is same in all inertial frames of reference, wouldnt the woman in the train see the lightning at the same time? Since the light from both ends have to travel the same distance. This puzzles me!! The fact that she will run into the front light earlier does not apply to her frame of reference. it is the man's frame of reference. so if we only consider the woman's frame of reference, shdnt she see the lightning at the same time? https://www.youtube.com/watch?v=wteiuxyqtoM – Patrik Ponjavić Nov 07 '17 at 21:21
  • Stafusa, they are working with formulas and I have no experience of doing so.. i just read some theories, and im very confused because in these coments on this page people are telling different things, and the youtube video makes no sense if we cant "run" away form light – Patrik Ponjavić Nov 07 '17 at 21:45
  • and in this video light behaves as same as bullet or speed of sound or any other speed – Patrik Ponjavić Nov 07 '17 at 22:05

1 Answers1

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Light travels at the speed of light regardless of your speed.

  • Light coming towards you would be going at the speed of light relative to you.
  • Light going in the same direction as you would be going at the speed of light relative to you.
  • That same light would also be going at the speed of light relative to a stationary observer that you both passed.

This is a fundamental principle of special relativity. The constant and the fastest speed is $c$ which is the speed of light in a vacuum. In other media, it may go slower.

For example, Cerenkov radiation occurs when particles go faster than the speed of light in the atmosphere. The particles come in at speeds that are very close to the speed of light in a vacuum but faster than light in the atmosphere. As the hit the atmosphere they slow down but for a brief while they are going faster than the speed of light in the atmosphere. Actually analogous to breaking the sound barrier.

Anyway, to return to your question, this may seem impossible. This is because you have familiarity with much slower objects and have built an intuition that, for example, if you were travelling at the speed of a bullet:

  • A bullet coming towards you would be going at twice the speed of the bullet relative to you.
  • A bullet going in the same direction would be stationary relative to you.
  • That same bullet would be going at the speed of the bullet relative to a stationary observer.

This intuition is correct only for non-relativistic speeds. The relativity equations also predict this for slower speeds and reduce to the Newtonian equations that yield this intuition.

At higher (relativistic) speeds what changes is time. Time is not the same for all observers and this is how the puzzle is resolved.

Dr Xorile
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