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A light clock is a mechanism that produces (and counts) equal time intervals.

Yes, but, do we understand correctly what the light clock is showing?

Since we don't know what the time exactly is, we can say that time is represented by a series of events (this event is not a point in Minkowski space-time). For example, this event can be a transition of photons from one point of space to the next as well as a mirror reflection.

In case in which we look at the time as a series of events, there must be an elementary event through which we can describe any complex event. So we can say that elementary event must be a permutation of points (switching places of two points) in space-time continuum.

So, instead of counting time intervals, we can say that a clock measures or counts permutations of points. Since it takes some time for two neighboring points to switch places, the clock simultaneously counts equal time intervals.

The definition of time remains correct.

Said permutation of points is also not time, but in a space-time continuum there is a posibility of movement that does not exist in Euclid's flat space.

Then we can say:

Time: Time is a posibility of permutation for points of space in space-time continuum.

Flow of time: Every new time period is represented by a new permutation.

Arrow of time: Since the reverse permutation is a new permutation, time moves in one direction only.

Is this view correct? Or does it violate any known rule in physics?

FPosta
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  • Theres a good discussion of this in Barbours The End of Time; have a look at the first few chapters; his thesis, amongst others, is that time is essentially motion. – Mozibur Ullah Dec 06 '17 at 08:40
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    @MoziburUllah Good, and some others associate time with movement. They only connect, but do not explain. My question is an explanation and it is not contrary to the definition. – FPosta Dec 07 '17 at 21:20

2 Answers2

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You need to be clear about what you mean by time, and in particular the difference between time and the flow of time. I go into this in What is time, does it flow, and if so what defines its direction? and that is really essential pre-reading for this question.

Any object traces out a world line in spacetime, which is just the set of all points that the object passes through. The length of the world line is given by the metric. That is suppose the position along the world line changes by distances in space $dx$, $dy$ and $dz$ and a difference in time $dt$ then the total distance moved along the world line is (assuming flat spacetime):

$$ c^2d\tau^2 = c^2dt^2 - dx^2 - dy^2 - dz^2 \tag{1} $$

where $c$ is the speed of light and $\tau$ is called the proper time. Equation (1) is a very important equation in special relativity and is called the Minkowski metric.

To understand the significance of the proper time suppose we are using the rest frame of the observer. In this frame the observer is not moving in the $x$, $y$ or $z$ directions because by definition in the rest frame the position in space is constant. That means $dx=dy=dz=0$ and only $dt$ is non-zero. Equation (1) simplifies to:

$$ c^2d\tau^2 = c^2dt^2 $$

or:

$$ d\tau = dt $$

So in the observer's rest frame the proper time is just the time measured on the observer's clock. That is, the observer's clock measures the distance travelled along the observer's world line. The flow of time just corresponds to motion along the world line.

So what about these light clocks? Well light has the property that its proper time is always zero i.e. $d\tau = 0$. If we go back to equation (1) and plug this in we get:

$$ 0 = c^2dt^2 - dx^2 - dy^2 - dz^2 $$

or:

$$ dt = \frac{\sqrt{dx^2 + dy^2 + dz^2}}{c} = \frac{dr}{c} \tag{2} $$

where I'm using $r$ for the total distance travelled in space, which using Pythagoras' theorem is simply:

$$ dr^2 = dx^2 + dy^2 + dz^2 $$

Equation (2) shouldn't be any great surprise, because it's just telling us that time is velocity divided by distance. It's importance is that it gives the coordinate time $dt$ in terms of a distance, and since we've already decided that proper time and coordinate time time are the same in our rest frame that means we can measure our motion along our world line by measuring how far light travels. That is, if we measure light to travel a distance $dr$ then we know we have moved a distance $cd\tau$ along our world line.

And this is why a light beam acts as a clock. Its motion in space tells us our motion in time.

Light clocks typically bounce the light beam between mirrors simply because that's a convenient way to do the the measurement. If the mirror spacing is $\Delta r$ then after each bounce we've moved a distance $c\Delta\tau = \Delta r$ along the world line. But there is no special significance to the bouncing. A light beam that just headed off to infinity would measure our time in the same way.

John Rennie
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  • I carefully read your answer and I did not find anything new in it. I did not find the answer to my question. – FPosta Dec 06 '17 at 11:32
  • @FPosta: Then I have obviously failed to understand what is confusing you. – John Rennie Dec 06 '17 at 11:35
  • If we do not know what is time, can we define it differently? If we have chosen the wrong definition for the time then we have break the development of physics. – FPosta Dec 06 '17 at 12:00
  • @FPosta I thought I had explained what time is. It's just the length measured along the world line. Time is just a dimension like the spatial dimensions. Light beams are just a convenient way to make this measurement, hence their use in light clocks. – John Rennie Dec 06 '17 at 12:26
  • Exactly, you gave an opinion that is not yours. I'm asking for arguments that my opinion is not good. – FPosta Dec 06 '17 at 17:06
  • @FPosta: what I described is not an opinion, it is how time is defined in relativity - both special and general. I have to confess I don't understand what you mean by Time is a possibility of permutation for points of space in space-time continuum but it clearly differs from the way time is defined in relativity. And since relativity has been experimentally tested to a high precision we believe it to the correct description. – John Rennie Dec 06 '17 at 17:12
  • The theory of relativity is correct, and whether the Minkowski space is correct. We think it is because some physicists think that time is 4 dimensions. Why do we use Riman's space and Hilbert's transformation if Minkowski is correct? Physics occurs in space-time for which we do not have the correct mathematical model. I do not want to argue about what others are doing, I'm asking if the definition of the time is correct. I agree that it is for mathematics, and is physical interpretation correct? – FPosta Dec 06 '17 at 18:00
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I think the term spacetime is just a source for confusion. It should be space movement, if anything. Any measurement of time, including your light clock example, takes a predictable repetitive movement pattern and uses it to measure other movements. So no, time does not exist. There is only movement. We can measure movement, and call the unit of measurement time, but that does not mean that time itself exists. Matter does, and movement does.

And I think that means thinking of time as a series of events is not really helpful. Maybe your observation of movement may not be continuous, but the underlying movement absolutely is.

Arwin
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