You could refer to Why is the Sun almost perfectly spherical?
Blockquote
The relationship between oblateness/ellipticity and rotation rate is treated in some detail here for a uniform density, self-gravitating spheroid and the following analytic approximation is obtained for the ratio of equatorial to polar radius
$$ \frac{r_e}{r_p} = \frac{1 + \epsilon/3}{1-2\epsilon/3}, $$
where $\epsilon$, the ellipticity is related to rotation and mass as
$$\epsilon = \frac{5}{4}\frac{\Omega^2 a^3}{GM}$$
and $a$ is the mean radius, $\Omega$ the angular velocity.
Putting in the relevant numbers for the Sun (using the equatorial rotation period), I get $\epsilon=2.8\times10^{-5}$ and hence $r_e/r_p =1.000028$ or $r_e-r_p = \epsilon a = 19.5$ km. Thus this simple calculation gives the observed value to a small factor, but is only an approximation because (a) the Sun does not have a uniform density and (b) rotates differentially with latitude in its outer envelope.
Now you can see from the formula above that $\epsilon$ decreases with increasing mass, decreasing rotation rate and decreasing mean radius. Thus objects with stellar masses will become progressively more spherical if they have smaller radii and slow rotation.
Neutron stars have $a \sim 10$ km, and the fastest rotation have $\Omega \sim 1000$ rad s$^{-1}$. For a 1.4 solar mass neutron star this yields $r_e/r_p \sim 1.0067$, i.e. more oblate than the Sun.
However, the rapidly-rotating "pulsar" phase of a neutron star's life is comparatively brief. After a million years or so, the rotation rate has slowed by many orders of magnitude (to periods of a few seconds or more) and will continue to decrease through the emission of magnetic dipole radiation. Once the neutron star above has slowed to $\Omega <60$ rad s$^{-1}$ (i.e. a rotation period $>0.1$ s) then it will become more spherical than the Sun.
The Sun is not going to be the record holder as far as "normal", non-degenerate stars go. There are low-mass M-dwarfs with rotation periods of $\sim 100$ days and radii about 0.1 that of the Sun, that will have $\epsilon \sim 10^{-9}$.
For a neutron star to beat this it would need to have a rotation period longer than about 20 seconds. Although such neutron stars have not been observed - because the pulsar mechanism switches off at periods longer than a few seconds, it seems likely that the majority of neutron stars in the galaxy rotate as slow or slower than this.
Thus my answer would be that the most spherical observed object would be something like Proxima Centauri with a rotation period of 83 days and about 0.15 times the radius of the Sun, the galaxy probably has several hundred million, slowly rotating old neutron stars that are more spherical than this.