Consider a particular compact 2D symplectic manifold $\mathcal{M}$ defined as follows:
- The topology of $\mathcal{M}$ is a 2-torus.
- Let $\theta$ and $\varphi$ be the coordinate patch on $\mathcal{M}$ with the following identifications: $\theta+ 2 \pi m \sim \theta$ and $\varphi + 2 \pi m \sim \varphi$ for integer $m \in \mathbb{Z}$. In another words, the torus was formed by gluing the opposite edges of a square $[0,2\pi)^2$.
- The symplectic form $\omega$ is given by $$\omega = d\varphi \wedge d\theta, \quad d\omega = 0.$$
Since the torus is flat, such a form exists globally.
Question: I want to see through the quantization of this symplectic manifold. According to literature, this should result in a finite-dimensional Hilbert space. How can this be shown explicitly? How can the matrices corresponding to $\hat{\theta}$ and $\hat{\varphi}$ be computed? How does this construction depend on $\hbar$?
Comment: I am sure that the Hilbert space should be finite-dimensional, because I've seen this claim made many times by multiple authors. E.g. Witten mentions it in his "QFT and the Jones polynomial" (see pdf, page 18/367, last paragraph before section 3.1).
Update: one can calculate the relevant $C^{*}$ algebra of observables by taking the basis of functions over the phase space:
$$ W_{n,m} = e^{i n \varphi + i m \theta} $$
and computing the Moyal bracket. Using the Kontsevich formula and making use of the fact that $\partial_{\mu} \omega^{\nu \sigma} = 0$ (because the torus is flat), one obtains the exponential:
$$ W_{n,m} * W_{n',m'} = e^{\frac{1}{2} i \hbar (m n' - n m')} W_{n+n', m+m'}. $$
(The involution is given by $W_{n,m}^{*} = W_{-n,-m}$).
One can then hope that this $C^{*}$ algebra acts naturally on some finite-dimensional Hilbert space, but I wasn't able to obtain such a space. I wonder if GNS construction can be employed here. Tried it for the following state: $$ \rho(W_{n, m}) = \delta_{n0} \delta_{m0}, $$
but the resulting Hilbert space seems to be infinite-dimensional. Not sure how to proceed further.