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In Paul Langacker's The Standard Model and Beyond, equation 3.50 states that, for a Lagrangian $\mathcal{L} = \mathcal{L}_0 + \mathcal{L}_1$, where $\left[ T^i , \mathcal{L}_0 \right] = 0$ and $\left[ T^i , \mathcal{L}_1 \right] \ne 0$, we would have

$$ \mathcal{L}' - \mathcal{L} = \left[ - \mathrm{i} \beta ^i T^i , \mathcal{L}_1 \right] = - \beta ^i \partial ^{\mu} J_{\mu}^i $$

For $J_{\mu}^i$ defined as following

$$ J_{\mu}^i = - \mathrm{i} \frac{\delta \mathcal{L}}{\delta \partial^{\mu} \Phi _a} L_{a b}^i \Phi _b - \mathrm{i} \frac{\delta \mathcal{L}}{\delta \partial^{\mu} \Phi _a^{\dagger}} \left( - L_{a b}^{i *} \right) \Phi _b^{\dagger} $$

I completely have no clue on how to prove the second equality in the first equation, could anyone help me on that?

zyy
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  • Possible duplicates: https://physics.stackexchange.com/q/56851/2451 , https://physics.stackexchange.com/q/110209/2451 and links therein. – Qmechanic Jul 16 '18 at 06:07

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