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Is there a tutorial explanation as to how decoherence transforms a wavefunction (with a superposition of possible observable values) into a set of well-defined specific "classical" observable values without the concept of the wavefunction undergoing "collapse"?

I mean an explanation which is less technical than that decoherence is

the decay or rapid vanishing of the off-diagonal elements of the partial trace of the joint system's density matrix, i.e. the trace, with respect to any environmental basis, of the density matrix of the combined system and its environment [...] (Wikipedia).

Qmechanic
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Nigel Seel
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3 Answers3

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The Copenhagen interpretation consists of two parts, unitary evolution (in which no information is lost) and measurement (in which information is lost). Decoherence gives an explanation of why information appears to be lost when it in actuality is not. "The decay of the off-diagonal elements of the wave function" is the process of turning a superposition: $$\sqrt{{1}/{3}} |{\uparrow}\rangle + \sqrt{{2}/{3}} |{\downarrow}\rangle$$ into a probabilistic mixture of the state $|\uparrow\rangle$ with probability $1/3$, and the state $|\downarrow\rangle$ with probability $2/3$. You get the probabilistic mixture when the off-diagonal elements go to 0; if they just go partway towards 0, you get a mixed quantum state which is best represented as a density matrix.

This description of decoherence is basis dependent. That is, you need to write the density matrix in some basis, and then decoherence is the process of reducing the off-diagonal elements in that basis. How do you decide which basis? What you have to do is look at the interaction of the system with its environment. Quite often (not always), this interaction has a preferred basis, and the effect of the interaction on the system can be represented by multiplying the off-diagonal elements in the preferred basis by some constant. The information contained in the off-diagonal elements does not actually go away (as it would in the Copenhagen interpretation) but gets taken into the environment, where it is experimentally difficult or impossible to recover.

Peter Shor
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    Thanks for actually answering the question. I am confirmed in my belief that it's quite a sophisticated concept. – Nigel Seel Jan 31 '11 at 16:13
  • Nice clear answer, Peter.+1 – Gordon Jan 31 '11 at 16:32
  • Indeed this basis question alone adds to the sophistication. Sometimes in calculations physicists might question whether the end result was dependent on choice of basis. I seem to recall this in the Penrose-Hawking debates on Black Holes, for example. – Roy Simpson Jan 31 '11 at 16:38
  • I really do not feel good that decoherence depends on basis. It is kind of weird. Why would be a basis more preferred than others? Suppose we write the density matrix in a basis which diagonalize it. Would decoherence happen in this case? – MOON May 15 '14 at 15:09
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    The physics doesn't depend on the basis. However, if you describe decoherence as "the decay or rapid vanishing of the off-diagonal elements of the partial trace of the joint system's density matrix", as the OP did, then it clearly depends on the basis. But this description is only true if you write the density matrix in the preferred basis of the interaction of the system and its environment. (And looking at the system in this basis makes decoherence much easier to understand.) – Peter Shor May 15 '14 at 16:46
  • @PeterShor I know next to nothing about decoherence (although I plan to learn about it now); are there descriptions of decoherence that do not appeal to a basis? If so, do you have any recommendations on good reading in that regard? – joshphysics May 16 '14 at 01:59
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    @joshphysics: sorry to take so long to reply. If you write everything in terms of the Lindblad equation, then there's no preferred basis involved. But this description is much more complicated (although in many cases it's also more accurate) than just saying decay of the off-diagonal elements. – Peter Shor Sep 10 '14 at 15:49
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Dear Nigel, the Wikipedia explanation is not too technical, but let me try to offer an even less technical one:

In ordinary quantum mechanics, the wave function remembers lots of complex numbers - the so-called probability amplitudes. These numbers may be added and combined in many ways and the absolute values of the squares of these sums are interpreted as probabilities.

This is different from classical (non-quantum) physics which contains no complex numbers "beneath" the probabilities.

Probabilistic statistical physics

However, there exists a statistical formulation of classical physics that does deal with probabilities, but ordinary "classical ones". There are no complex numbers beneath them. There simply exists a set of possibilities - e.g. that you throw dice and you get 1,2,3,4,5, or 6 - and classical physics with an uncertain, probabilistically given initial state, may calculate that each of these final outcomes has probability of 1/6.

In this probabilistic classical physics, one doesn't claim to know the positions and momenta $p,x$ of all particles. Instead, one works with the probabilistic distribution function $\rho(x_i,p_j)$ that is a function of all the possible positions and momenta of all the particles. The function describes the probability density that the particles are located in a small volume around a given point $(x_i,p_i)$ of the phase space.

It's the latter form of classical physics that quantum mechanics reduces to after decoherence. Decoherence produces a preferred set of possibilities that may be measured and it calculates the probabilities of each of them, much like you would in the probabilistic version of classical physics. But of course, the underlying theory is still quantum theory and it can only make probabilistic predictions. So decoherence will never actually find a way to decide which of the outcomes is realized.

In other words, there is no "collapse" into a single outcome, just like there is no collapse in the probabilistic classical physics. The density matrix, obtained by tracing the wave function, is not an "objective state of reality": there exists no "objective state of reality". Much like the classical distribution function, it's just a probability distribution describing our incomplete state of knowledge.

The role of decoherence is to choose a preferred set of outcomes that can be measured - e.g. "alive cat" and "dead cat" - and explain why all the other linear superpositions of the preferred outcomes are illegitimate. This result "bans" further interference and other typically quantum phenomena. That allows us to think about the evolution using the classical intuition. But it's still true that the evolution is indeterministic - and it will always be.

A review of decoherence

For others, a more technical explanation of decoherence is e.g. here:

http://www.karlin.mff.cuni.cz/~motl/entan-interpret.pdf

Luboš Motl
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  • If we're doing a localisation experiment for a bound state, then the traditional story is that we can start with a wave-function with non-zero values across the potential well. After a position experiment we have a "top hat" function to the precision of our measurement. The wave function "collapsed". However, we're talking localisation (position basis) all the time. Does decoherence add to, or modify, or update this story? – Nigel Seel Jan 31 '11 at 10:35
  • So you're suggesting that decoherence transforms the original wavefunction into a collection of top-hat functions, all centred around different points within the well and observation will pick out one of these? – Nigel Seel Jan 31 '11 at 10:38
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    The last four pages of the PDF linked to by Luboš is as clear and concise a description of decoherence (and as elementary, notwithstanding Luboš saying that it's "more technical") as anything I've seen elsewhere. +1 for that. – Peter Morgan Jan 31 '11 at 13:38
  • Nice lecture notes. +1 – Gordon Jan 31 '11 at 16:31
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    I'm going to have to add my upvote for the paper Lubos has linked to. – Marty Green May 26 '11 at 03:31
  • Sorry, my pet peeve: "Wikipedia explanation is not too technical". Don't assert power on non-experts by saying things are easy, trivial or simple, they aren't. If you understood something 10 years ago, it becomes as trivial for you as 1+1, but not automatically everyone else. That's one of the most important things one need to learn when teaching people many levels below them. – Calmarius Apr 04 '16 at 13:43
  • Dear @Calmarius, the Wikipedia article on decoherence has almost 1,000 edits from very many different editors, low number of equations, and especially simple enough equations that only need some basic undergraduate linear algebra, and everyone with the understanding of the basic formalism of QM may get this article. At least approximately, it makes sense to divide texts to very technical and not too technical and while there are very technical texts on Wikipedia, the article on decoherence isn't one of them. – Luboš Motl Apr 05 '16 at 06:24
  • Things generally become easier to understand to people who have studied things, who have a talent for things, or who are just smarter, but that doesn't mean that it's "not kosher" to express opinions about which texts are technical and which texts are not. So if your attempt was to bully me and declare the rating of "technical vs not technical" to be political incorrect, I have to assure you that you have failed and I will never stop using these important adjectives. – Luboš Motl Apr 05 '16 at 06:26
  • The Wikipedia article may still be incomprehensible to average high school students or adults with the same physics and mathematics background - one needs some college-like training related to sciences or mathematics. But it's questionable whether this is a problem. I don't think that people outside the "college-like STEM community" should care about the meaning of decoherence. It only creates chaos when people who obviously don't know much about physics in any sense are led to use words such as "decoherence". – Luboš Motl Apr 05 '16 at 06:28
  • Lubos, the link http://www.karlin.mff.cuni.cz/~motl/entan-interpret.pdf says "not accessible. – anna v Oct 06 '17 at 15:10
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    @annav - take it e.g. from https://1drv.ms/b/s!Ahh3_wb6HNicgU3OjG-gdXNacWRT – Luboš Motl Oct 11 '17 at 15:11
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The Wikipedia article is rather a lengthy description of decoherence which undoubtedly also prompts this question. Part of the reason is that decoherence is not, in a certain sense, a truly fundamental mechanism amending quantum theory, but an applied mechanism introduced to "explain" collapse using ideas from Statistical Mechanics (those density matrices and concepts of "bath"/environment) supplementing those of quantum mechanics.

Borrowing a key equation from the Tutorial mentioned by Lubos, one writes:

$H = H_c + H_e + H_i$

for the Hamiltonian $H$ understood from a decoherence perspective: its ingredients are $H_c$ which is the simpler component (= system under study) Hamiltonian discussed in elementary textbooks; $H_e$ is the environment and $H_i$ the Interaction (including the experiment).

So this is saying "dont just look at the system alone; look at the entire environment+system" from a conceptual perspective. Abstractly there is no collapse here; although thermodynamic-like arguments are then used to give the (local) appearance of collapse.

To follow this up a Tutorial can do two things:

(1) Explain the thermodynamic aspect a bit more;

(2) Explain what happens to "collapse" at the $H$ level.

Hopefully this helps a little.

Roy Simpson
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