1

My textbook [1] says in order to determine the De Broglie wavelength of an $e^-$ in a hydrogen atom at energy level $n=2$, we can determine its kinetic energy first by finding its total energy from $E=-13.6/n^2$ then determine its De Broglie wavelength accordingly.

But isn't the total energy of the electron at $n=2$ refers to its potential and kinetic energy? How can we simply take the negative of the electron's total energy and call it the electron KE? This implies that at $n=\infty$ then electron's KE is 0; vice versa when $n=0$ then electron's KE is $\infty$.

References:

  1. K. A. Tsokos, "Physics for the IB Diploma Coursebook" 6th Edition
Qmechanic
  • 201,751

2 Answers2

1

Hints:

  1. Note that the principal quantum number $n\in\mathbb{N}$ cannot be zero.

  2. Use the virial theorem. See also this related Phys.SE post.

Qmechanic
  • 201,751
-1

It's a formalism from harmonic oscillator, so that when electron come from $n=2$ to $n=1$, it releases energy.

Also, without nature presetance of fields or confirment, $H$ can be ionized if you insist, there are just so many quantized value that one could take. Calling it KE is from hamiltonian operator. It's a correspondance with classical physcis.