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am not familiar with QM , and i have checked web many times to know wether all measured Quantities of any arbitray system should be real since it is Hermitian ?

  • Yes, we use Hermitian operators because everything we measure (positions, velocities, momenta, accelerations, forces, energies, etc.) is real, not complex. So we need the eigenvalues to be real. – G. Smith Aug 12 '19 at 23:04
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    possible duplicates: https://physics.stackexchange.com/q/82613/84967, https://physics.stackexchange.com/q/27038/84967, https://physics.stackexchange.com/q/75401/84967, https://physics.stackexchange.com/q/39602/84967 – AccidentalFourierTransform Aug 12 '19 at 23:10
  • Your question is kind of convoluted and the wording is difficult to decipher. The possible measurements of a QM system will be the eigenvalues of the Hermitian operator and these are real. The requirement of a real valued observable forces the operators to be Hermitian. –  Aug 13 '19 at 03:00

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