Suppose you have a system described by the following Lagrangian: $$L=(1-gq²)\dot{q}^2/2.$$
How would you quantize this theory? Do you need to symmetrize the Hamiltonian before promoting the coordinate and momentum to operators?
Suppose you have a system described by the following Lagrangian: $$L=(1-gq²)\dot{q}^2/2.$$
How would you quantize this theory? Do you need to symmetrize the Hamiltonian before promoting the coordinate and momentum to operators?
The 1D particle $L=\frac{1}{2}m(q)\dot{q}^2$ with a position-dependent mass $m(q)$ has classical momentum $p=m(q)\dot{q}$ and Hamiltonian $H=\frac{p^2}{2m(q)}$.
The Hamiltonian operator should be a self-adjoint operator. However this does not make quantization unique.
Following the same quantization strategy as my Phys.SE answer here where the mass $m(q)$ is viewed as the lone component $g_{qq}$ of a 1D metric, in the Schrödinger representation the momentum operator becomes $$ \hat{p}~=~ \frac{\hbar}{i} m(q)^{-1/4}\frac{\partial }{\partial q} m(q)^{1/4}, $$ and the Hamiltonian operator becomes $$ \hat{H}~=~ -\frac{\hbar^2}{2} m(q)^{-1/4}\frac{\partial }{\partial q} m(q)^{-1/2} \frac{\partial }{\partial q}m(q)^{-1/4}. $$