According to the equivalence principle, a free radially-falling observer moving towards black hole does not see Hawking radiation. Does a free falling shell see Hawking radiation? If not, how does the radiation "goes through" the shell and reach the infinity?
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1why would the equivalence principle imply that? – Dec 27 '19 at 20:55
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1See also this question – Linas Jun 07 '21 at 02:30