Graph of $dQ/dt$ discontinuous

Asked May 28 '20 at 19:38

Active May 28 '20 at 19:45

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Charge is quantised then why how do we define $dQ/dt$ as current when graph of $Q$ v/s $x$ will be discontinuous and hence non-differentiable.

Is it an approximation we use?

edited May 28 '20 at 19:45

Qmechanic

asked May 28 '20 at 19:38

Ameya M

0 Answers0