I was wondering if there is a way to prove the length contraction without using the time dilation? because every time I see a derivation to length contraction it comes with the time dilation and start based on it.
1 Answers
It depends on your postulates: on what premisses are you going to build your theory. If you take the Lorentz transforms as your premisses then you don't really use time dilation to establish length contraction. But you still need to consider time in order to understand length contraction. In particular you need to realise that in a frame, S, in which a body is moving (in the +$x$ direction, you must make simultaneous measurements of the positions of $x_A$ and $x_B$ of A and B on the body in order to measure the distance ($x_B-x_A$) in your frame. In the S' frame, in which the body is stationary there is no need for simultaneous measurement of $x'_A$ and $x'_B$. Using the Lorentz transform for displacements parallel to the relative velocity between frames, and the simultaneity of measuring $x_A$ and $x_B$ we have: $$x'_A = \gamma(x_A-vt)\ \ \ \ \text{and}\ \ \ \ x'_B = \gamma(x_B-vt)\ \ \ \ \text{so}\ \ \ \ x'_B-x'_A=\gamma(x_A-x_B) $$ Since $\gamma > 1$ we have $x_A-x_B<x'_B-x'_A.$

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What I want to do is prove the $\gamma$ in the length contraction without using the time dilation. As if I didn't know about Lorentz transformation – RendezvousRama Nov 26 '20 at 23:01
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2What are your premisses, your starting assumptions? – Philip Wood Nov 26 '20 at 23:05
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The assumptions are: Let there be a photon emitting from A (which has a mirror) to B (Also has a mirror) and both of them are in a parallel line with the velocity $v$ (which is all the system velocity), for the stationary observer the distance between A and B is $X$. How can I prove that it will have a length contraction for the outside frame? – RendezvousRama Nov 26 '20 at 23:15
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2You have described a set-up. You need assumptions, for example about light, time and space on which to build an argument! I like to start with Einstein's postulates supplemented with the isotropy of space and proceed, for example as Rindler does (Introduction to Special Relativity, Second edition, 1990) to the Lorentz transforms. I sense that this is not the sort of answer that you are looking for. You may well get answers more to your taste; it's early days. – Philip Wood Nov 26 '20 at 23:48