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In the quantum version of the infinite well, the energy eigenvalues can be precisely determined.

The energy is all in the form of kinetic energy, $E=\frac{p^2}{2m}$, and so, classically, the magnitude of the momentum should be exactly known as well.

But the peaks in $ϕ(p)$ have a finite spread (seen in Fig) enter image description here

Why does this happen?

Qmechanic
  • 201,751
  • The peaks have finite spread, because you are still in quantum domain, looking at the wave function squared. – Roger V. Jan 19 '21 at 09:43
  • Possible duplicates: https://physics.stackexchange.com/q/362305/2451 , https://physics.stackexchange.com/q/233266/2451 and links therein. – Qmechanic Jan 19 '21 at 09:47

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