Why not make it simple? Let's say, that here on Earth nothing else changes, just that the atmospheric density decreases to your required level (even if it is impossible for the sake of argument let's say that). What do you see when you look up? Good old blue. Why?
The answer is Rayleigh scattering. If nothing else changes, this is the dominant form of scattering when the particles (atmospheric molecules) are much smaller then the wavelength of (visible 400-700nm) light. This is why the sky is blue now, and atmospheric density alone will not change the color itself.
After all, you have relatively small thickness near zenith, which makes most of the light scattered to you not too extincted due to Beer-Lambert law, while near the horizon the thickness is much larger, and the light scattered into the observer, in addition to becoming bluer due to Rayleigh scattering depending on wavelength, becomes also redder due to extinction along this long path. The combination of this bluing and reddening effects gives a color closer to white (which you can see in the daytime simulation above), or reddish-orange (in the twilight).
Why is the sky *uniformly* blue?
Will it change the shade? I bet it will somewhat, maybe it will be a different shade of blue.