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I do not know the rules (mathematica rules) in order to perform the following calculation:

Lets say we have a $2$ particle system. Each particle has its own eigenbasis:

$|\phi_r\rangle$ is an ONS of System $S$ (particle 1).

$|\phi_a^\prime\rangle$ is an ONS of System $S'$ (particle 2).

Then if the whole system is in an arbitrary state $|\psi\rangle$, we can write:

$|\psi\rangle = \sum\limits_{r,a} c_{ra}\, |\phi_r\rangle \bigotimes |\phi_a^\prime\rangle $

Now if I want to find the expectation value of an observable in the system $S$ (and ignore $S'$) I would do the following:

$\langle \psi|A\bigotimes I|\psi\rangle = ( \sum\limits_{r,a} c_{ra}^*\, \langle \phi_r| \bigotimes \langle \phi_a^\prime|) A\bigotimes I( \sum\limits_{s,b} c_{sb}\, |\phi_s\rangle \bigotimes |\phi_b^\prime\rangle$

How do I solve this equation? Like what are the rules in this case?

imbAF
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  • To clarify: (1) Does ONS mean orthonormal system? (2) Did you mean "mathematical rules" instead of "mathematica rules"? (They're both meaningful, but the meanings are different. Mathematica is a symbolic calculation software package.) – Chiral Anomaly Apr 17 '21 at 21:03
  • What do you mean by 'solving' this equation? Do you mean how to simplify this equation? – Tobias Fünke Apr 17 '21 at 21:05
  • correct, 2)mathematical, like what are the rules to solve this type of thing with that tensor notation or product thing,3)yes how to simplify it
  • – imbAF Apr 17 '21 at 21:07
  • When $V$ and $W$ are inner product spaces, then for pure tensors we have $\langle v_1\otimes w_1, v_2\otimes w_2\rangle = \langle v_1,v_2\rangle\langle w_1,w_2\rangle$. Extending by bilinearity gives you the inner product on $V\otimes W$. – doetoe Apr 17 '21 at 22:04
  • KroneckerProduct[] is the function you want to perform tensor products in Mathematica. – AccidentalTaylorExpansion Apr 18 '21 at 09:02