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I need to rewrite expressions of the type $(\partial_\nu A_\mu)(\partial^\mu A^\nu)$ from the "covariant" form, to non-covariant form (so with roman indices). Here the greek indices run from 0 to 3 and the roman indices from 1 to 3. My attempt at it looks like $$(\partial_0A_0)(\partial_0A_0)-(\partial_0A_j)(\partial_0A_j)-(\partial_iA_0)(\partial_iA_0)+(\partial_iA_j)(\partial_i A_j)$$

I am not sure if the signs are correct. Do "space indices" carry the minus even if the greek letter index is downstairs, so that everything turns out positive? An example is the expression $(\partial_0A_\mu)(\partial_0A^\mu)$. Would it be written non-covariantly as $(\partial_0A_0)(\partial_0A_0)+(\partial_0A_i)(\partial_0A_i)$ or with the minus sign as $(\partial_0A_0)(\partial_0A_0)-(\partial_0A_i)(\partial_0A_i)$?

Qmechanic
  • 201,751

1 Answers1

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Your attempt is correct. If one wants to compute $$ (\partial_0 A_\mu) (\partial_0 A^\mu) = \eta^{\mu \nu} (\partial_0 A_\mu) (\partial_0 A_\nu) $$ it is indeed \begin{align} \eta^{\mu \nu} (\partial_0 A_\mu)(\partial_0 A_\nu) &= \eta^{00} (\partial_0 A_0)(\partial_0 A_0) + \eta^{ij} (\partial_0 A_i)(\partial_0 A_j) \\ &= +1 (\partial_0 A_0)(\partial_0 A_0) - \sum_i (\partial_0 A_i)(\partial_0 A_i) \end{align} where one can remove the summation sign if they wish.

user1379857
  • 11,439