Consider an unstable potential of the form $$V(\phi) = - \lambda \phi^n $$ with $\lambda > 0$ (hence unstable). Now due to quantum fluctuations, a particle at the top is going to roll down. So what is the lifetime of the particle at the maxima of the potential?
Nima in his 2019 TASI lecture on EFT gives a hand-wavey argument via dimensional analysis in 4D. Particularly, the lifetime $\tau \sim \frac{1}{M}$ where $M$ is the mass dimension of the proportionality constant in the potential. While it works for $n=2,3$, at $n=4$ he derives the lifetime from some other argument to be $\tau \sim e^{1/\lambda}$ . For $n>4$, again this procedure doesn't give the right answer. e.g. for $n=6$, $\tau \sim \sqrt{\lambda}$ which is incorrect/opposite to what you expect.
So is there a way to derive the lifetime in a more concrete way and which works for any power of potential (in any number of spacetime dimensions)?