I just want to know if in an exponential function $e^x$, will $x$ always be dimensionless? If so, Why?
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2Does this answer your question? Exponential or logarithm of a dimensionful quantity?. See also, for instance, this one, or this one or this one, etc. – Yvan Velenik Jun 19 '21 at 08:05
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Yes thanks a lot – Ritvish Jun 19 '21 at 08:12
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1Why should this question be reopened? As I show in my comment above, there is already a multitude of similar questions on this site. It is insane to continue adding new ones all the time. – Yvan Velenik Jun 19 '21 at 09:08
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Maclaurin series for the exponential function
$$e^{x} = \sum_{n=0}^{\infty} \frac{x^{n}}{n!}$$
So to be able to sum this up you have to have $x$ dimensionless.

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So whenever we have any exponential function,the dimensions of the power will always be dimensionless? – Ritvish Jun 19 '21 at 08:11
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Yes, otherwise the "answer" would be dependent on specific units chosen for $x$, to say the least. – Vladimir Kalitvianski Jun 19 '21 at 08:17