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I just want to know if in an exponential function $e^x$, will $x$ always be dimensionless? If so, Why?

1 Answers1

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Maclaurin series for the exponential function

$$e^{x} = \sum_{n=0}^{\infty} \frac{x^{n}}{n!}$$

So to be able to sum this up you have to have $x$ dimensionless.

Monopole
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