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Two possible representations of the four-dimensional Hilbert space are the 4D column vectors or the 2x2 Hermitian matrices. For example, consider the two following representations of an orthonormal basis:

$$\underbrace{\left\{\begin{bmatrix}1\\0\\0\\0\end{bmatrix},\begin{bmatrix}0\\1\\0\\0\end{bmatrix},\begin{bmatrix}0\\0\\1\\0\end{bmatrix},\begin{bmatrix}0\\0\\0\\1\end{bmatrix}\right\}}_\text{4D column vector representation}\quad\text{and}\quad\underbrace{\left\{\frac{1}{\sqrt{2}}\begin{bmatrix}1&0\\0&1\end{bmatrix},\frac{1}{\sqrt{2}}\begin{bmatrix}0&1\\1&0\end{bmatrix},\frac{1}{\sqrt{2}}\begin{bmatrix}0&-i\\i&0\end{bmatrix},\frac{1}{\sqrt{2}}\begin{bmatrix}1&0\\0&-1\end{bmatrix}\right\}}_{2\times2\text{ Hermitian matrix representation}}$$

Where an appropriate inner product for the matrix representation can be shown to be defined by $\langle \boldsymbol A|\boldsymbol B\rangle\equiv\operatorname{tr}\left(\boldsymbol A^\dagger\boldsymbol B\right)$.

I was wondering whether there are any situations where it would be helpful or be more intuitive to represent the state kets as matrices such as above?

To clarify, I know that we often write states as density matrices ($|\psi\rangle\langle\psi|$ - example pure state) to allow for mixed states. I am not interested in this but interested in matrix representations of kets.

Chris Long
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  • For two qubits, the Schmidt decomposition of a n entangled state corresponds to the SVD of the 2x2 matrix representation described. This question feels like its going to end up as a 'big list' question though which are discouraged. – jacob1729 Jul 14 '21 at 23:40
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    I think that there are many situations where it would be helpful or be more intuitive to represent the states as matrices. It's helpful in cases of product states $:\boldsymbol{\xi}\boldsymbol{\otimes}\boldsymbol{\eta}:$ where $:\boldsymbol{\xi}\in \mathrm H_\alpha, \boldsymbol{\eta}\in \mathrm H_\beta:$ and very convenient if the Hilbert spaces $: \mathrm H_\alpha, \mathrm H_\beta:$ are of the same dimension since then the matrices are square (1)... – Frobenius Jul 14 '21 at 23:43
  • @jacob1729 Thank you for the link I will have a read later when I get some time! In regards to the 'big lists' being discouraged is that questions that incite them or answers of that form? If it is questions I apologise and will close my question. – Chris Long Jul 14 '21 at 23:46
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    ...(1) See here How to understand the makeup of neutral pi and eta mesons? how the states of mesons of three quarks $:\boldsymbol{u},\boldsymbol{d},\boldsymbol{s}:$ are represented by $:3\times 3:$ matrices in equation (009). Also note that the inner product in the product Hilbert space of two states $:\mathrm{X},\mathrm{Y}:$ is represented by the trace $:\langle \mathrm{X},\mathrm{Y}\rangle =\mathrm{Tr}\left[\mathrm{X}\mathrm{Y}^{*}\right]:$ (2)... – Frobenius Jul 14 '21 at 23:46
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    ...(2) in equation (016) in agreement to your definition. – Frobenius Jul 14 '21 at 23:47
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    In my S E C O N D___ A N S W E R here Total spin of two spin- 1/2 particles you could see the representation of product states $:\boldsymbol{\xi}\boldsymbol{\otimes}\boldsymbol{\eta}:$ in general, see equation (19). Usually we $''$arrange$''$ the matrix in a column matrix according to the scheme under this equation and described by equations (20a,b,c)...(3) – Frobenius Jul 15 '21 at 00:13
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    (3)... Only under this $''$arrangement$''$ the product of two transformations $:\mathrm{A}\boldsymbol{\otimes} \mathrm{B}:$ is represented conveniently by a matrix as provided by equation (47) in my T H I R D___ A N S W E R. – Frobenius Jul 15 '21 at 00:14
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    Thank you, very comprehensive @Frobenius – Chris Long Jul 17 '21 at 09:16
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    @Chris Long : Welcome, Chris. The 25 days membership, the 21 very good answers make me suspect that you will grow up to a "terrible" user herein PSE. Good Luck. – Frobenius Jul 17 '21 at 09:24

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