Conservation of a charge $$ Q = \int dV \, j^0 $$ follows from current conservation $$ \partial_\mu j^\mu = 0 $$ and $$ \dot{Q} = - \oint dS \, j = 0 $$ where the Gauß divergence theorem has been applied (and where sufficiently localized charge and current distributions are assumed).
Lorentz invariance of charge should follow from an appropriate definition $$ Q[V] = \int_V dV \, j^0 \to \int_V dV_\mu \, j^\mu $$ and using the invariance of $$ dV_\mu \, j^\mu. $$
The integral can also be defined using the trick
$$ Q[V] = \int_M d^4x \, j^\mu \, \partial_\mu \theta(v_\nu x^\nu) $$
where the resulting $\delta$-function projects to the 3-manifold $V$.
Usually (e.g. Weinberg „Gravitation“ 2.6) the calculation of the integral is done using
$$ \partial_\mu j^\mu = 0 $$
and therefore writing
$$ j^\mu \, \partial_\mu \theta = \partial_\mu (j^\mu \, \theta) $$
The last trick means that the proof of the Lorentz invariance of a charge presupposes the conservation of the same.
- Questions:
- Is there a way to proof Lorentz invariance of a charge without using charge conservation?
- If not, what does it mean in case of charges that are not conserved? (in quantum field theories a conserved classical charge may be no longer conserved due to quantum anomalies; such an anomaly does not break Lorentz symmetry)
Remark: The fact that for each $V$ the charge $Q[V]$ is a Lorentz scalar is trivial b/c for fixed $V$ the term $dV_\mu \, j^\mu$ is a scalar. The question is not about this trivial fact but about the proof of
$$Q[V^\prime] = Q[V]$$
that means, which charge is measured by two different observers O, O’ represented by $V, V^\prime$.