The bosonic path integral computes transition amplitudes. E.g. for a scalar field $\phi$, the amplitude between state $|\phi_1\rangle$ on Cauchy surface $\Sigma_1$ and $|\phi_2\rangle$ on $\Sigma_2$ is given by \begin{equation} \langle \phi_2|U_{\Sigma_1\to\Sigma_2}|\phi_1\rangle=\int_{\phi|_{\Sigma_1}=\phi_1}^{\phi|_{\Sigma_2}=\phi_2}D\phi e^{iS[\phi]}.\tag{1} \end{equation} (I'm writing $U_{\Sigma_1\to\Sigma_2}$ for the unitary evolution between the Cauchy surfaces, and $S$ for the action).
I'd like to know whether the fermionic path integral admits a similar interpretation. More precisely, if $\psi_1, \psi_2$ are Grassman-valued fields on $\Sigma_1,\Sigma_2$ (resp.), let us define: \begin{equation} Z[\psi_1,\psi_2]\equiv \int_{\psi|_{\Sigma_1}=\psi_1}^{\psi|_{\Sigma_2}=\psi_2}D\psi D\bar{\psi}e^{iS[\psi,\bar{\psi}]},\tag{2} \end{equation} where the path integral is understood to be fermionic.
What is the meaning of $Z[\psi_1,\psi_2]$? It's not clear how it can be a transition amplitude, since $\psi_1$ and $\psi_2$ don't seem to label states in the Hilbert space in any obvious way. (Compare this with the scalar case, where $\phi_1$ and $\phi_2$ label corresponding field eigenstates). But perhaps there is some nice way to associate $\psi_1$ and $\psi_2$ with states in Hilbert space, in such a way that $Z[\psi_1,\psi_2]$ gives the amplitude between the associated states.
If there is no interpretation of $Z[\psi_1,\psi_2]$ as a transition amplitude, then my question becomes: what is the reason for introducing such path integrals at all?