Suppose I am standing in a station with a light clock(1).(A clock where light is bouncing up and down with a height of h.).Lets calculate the time seeing light clock(1) t=h/c (here c is the speed of light) and a train is passing through the station with a velocity of v.And there is another light clock(2) inside the train.Lets calculate the time seeing light clock(2).Now we get t=D/c. And here D is not equal to h since the train is moving and light needs to pass some extra distance.So we get two different time in same reference frame.Why?
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Time is very different from what your everyday experience and classical physics would lead you to expect. See What is time, does it flow, and if so what defines its direction? – mmesser314 Mar 14 '22 at 22:19
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What, exactly, don't you understand? – Marco Ocram Mar 14 '22 at 22:37
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There are a ton of questions and answers about the light clock here. I marked this as a duplicate of one. If that one doesn’t answer your question then please read a few more. If none of them answer it then please write a new question, link to the ones you read, and explain what is missing from the linked questions and answers – Dale Mar 14 '22 at 22:44
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I had lunch today at 1pm and dinner at 6pm, though I sat perfectly still all day. How can these events occur at different times in the same reference frame? – WillO Mar 14 '22 at 23:20