For weak gravitational fields, which means anywhere that isn't near a black hole, the gravitational time dilation can be related to the gravitational potential energy by the equation:
$$ \frac{\tau}{t_\infty} = \sqrt{1 - \frac{2\Phi}{c^2}} $$
In this equation $\tau$ is the time that passes inside the gravitational field, $t_\infty$ is the time measured far away where the gravitational field is zero, and $\Phi$ is the Newtonian gravitational potential energy. This is known as the weak field approximation and it is an excellent approximation for the Earth's gravitational field.
Since the right hand side of the equation is less than one we can immediately see that $\tau < t_\infty$ i.e. time passes more slowly in the gravitational field, and this is what we mean by the gravitational time dilation.
Suppose the ISS and ISS2 orbit at a distance $r$ from the centre of the Earth. The Newtonian gravitational potential energy is $U = GM/r$, and substituting this into our equation gives:
$$ \frac{\tau}{t_\infty} = \sqrt{1 - \frac{2GM}{c^2r}} $$
And in fact this is an exact result that is the same as predicted by general relativity, though this is due to the way the $r$ coordinate is defined in GR so we shouldn't read too much into this.
Anyhow, if the masses of ISS and ISS2 can be ignored they will have the same gravitational potential energy since they are the same distance from the Earth, and therefore the gravitational time dilation will be the same.
If you include the masses of the space stations then their GPEs will be slightly different. A clock in ISS2 as a slightly greater GPE because the $2m$ mass of ISS2 will increase the GPE more than the $m$ mass of ISS1. As a result a clock in ISS2 will run slightly slower than a clock in ISS1, though both clocks will run faster than a clock on the surface of the Earth.
Actually calculating the difference would be complicated as it would depend on the exact shape of the space station and where in the space station the clocks were located. In any case the difference is going to be immeasurably small since the gravitational fields produced by the space stations' masses are tiny compared to the gravitational field of the Earth.
One last comment: an object orbiting the Earth experiences time dilation due to both the gravitational time dilation and the Lorentz time dilation due to its velocity. However in this case it won't affect the comparison between the two space stations since both will have the same orbital velocity.