Consider a cement block of the same density as sea-water resting on the (perfectly polished) seafloor. I also assume the side-faces of the cement block are highly polished, so that no vertical hydrostatic forces can attack on them. A cable is attached to the top of the block.
My question ist: How much force must one apply to the cable before the cement block begins to lift off the seafloor?
The normal response would be to say that only a negligible force is needed - as the block is practically suspended in the water.
However, as the bottom surface of the cement block is not in contact with the water, it is NOT experiencing the hydrostatic pressure from below - only from above.
Before the crane starts lifting, the (zero-sum) forces on the cement block are:
$$F_{Seawater Pressure} +F_{Gravity on Cement Block} - F_{Seafloor Resistance} = 0$$
as the crane starts applying Force, the Seafloor will reduce its Resistance in the same measure, leaving the forces on the cement block zero:
$$F_{Seawater Pressure} +F_{Gravity on Cement Block} - (F_{Seafloor Resistance}+F_{Crane}) = 0$$
Just before the Cement block lifts, the Seafloor will stop applying Force and the Crane will be applying the only upward Force:
$$F_{Crane} = F_{Seawater Pressure} +F_{Gravity on Cement Block}$$
Once the Cement block lifts off the sea-floor, hydrostatic pressure kicks in on the lower cement surface, suspending the block, but before that - boy does it take a lot of force to lift it!
What is wrong with this reasoning?