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If I have a cube that is moving at a velocity of $v$ and spinning at an angular velocity of $\omega$, how can I determine the instantaneous velocity vector of one of the vertices of the cube?

What if the cube is accelerating? And what if it had angular acceleration, $\alpha$? Would this change the method of calculation?

Would it be possible to get an acceleration vector?

Daniel
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The total velocity will be the sum of the translational and rotational velocities. Thus $$ \mathbf{v}_\text{net}=\mathbf{v}_\text{COM}+\mathbf{\omega}\times \mathbf r, $$ where $\mathbf r$ is the vector from the center of mass to the vertex, and $\mathbf v_\text{COM}$ is the center of mass velocity.

Emilio Pisanty
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