24

I was making a school project for my younger brother. Two bottles are taken and attached to each other using a pipe. To one bottle, the pipe is inserted almost at the bottom and the other almost at the middle of bottle. When i filled one bottle with water, at equilibrium, both the bottles had same height of water from ground.

Two bottles connected with a pipe

However, I predicted that the water levels should be same in both the bottles not with respect to the ground, but to the point where pipes are attached to the bottles, i.e., the height of water columns above the point of attachment should be same. But the height in first bottle is more than that in the second bottle.

I think that the pressure should be same at both ends of the pipe at equilibrium and that pressure is $hρg$. Since the column height above pipe attachment is not same in both the bottles, the pressure at both ends should be different and water should still flow, which is not the case.

Where am I wrong?

Wrzlprmft
  • 6,242
  • 8
    "I predicted that the water levels should be same in both the bottles not with respect to the ground, but to the point where pipes are attached to the bottles" – Imagine two separate pipes, one goes /, the second goes . What now? – Kamil Maciorowski Jan 04 '23 at 06:53
  • Empty the bottles. Now slowly fill the green / left bottle until its water level is just below where the straw enters the clear / right bottle. Note what happens to the water level in the straw. Now continue slowly filling the green bottle. What happens? – Arthur Jan 04 '23 at 10:12
  • 1
    @KamilMaciorowski or just bend the pipe coming out of the bottom of a bottle back so it empties into the bottle. Or just stick a straw into a bottle. If the pressure's the same at both ends, the drink should spontaneously fountain out of the straw like it would out of a hole in the bottle... – Christopher James Huff Jan 04 '23 at 17:43

5 Answers5

34

This is an excellent question because the answer seemingly defies common-physics-sense.

Wrzlprmft's answer clarifies that the connecting pipe can also be treated as a vessel. But that doesn't explain why the system is in equilibrium. Let me show you why.

Here an image can speak a thousand words.

enter image description here

The distances are labeled in standard font, and the labels in bold are pressures. Also, the pressure does not depend on the shape of the connecting pipe. You can see that the vessel pressure balances out the pressures at either end of the connecting pipe at the corresponding points. Hence, the system is in equilibrium.

Notice that $a$ and $b$ can be anything here. So no matter where you attach the pipe, this equilibrium condition will still hold.

AlphaLife
  • 11,871
16

You have built some communicating vessels and fell victim to a variant of the hydrostatic paradox. In communicating vessels, the water level is the same everywhere with respect to the ground.

I think that the pressure should be same at both ends of the pipe at equilibrium and that pressure is $hρg$.

This is where you made an error: The pressure is not the same at both ends of the pipe. Instead, since the pipe is a vessel as well, pressure increases when going from the top right to the bottom left, following the same law.


To see the effect you are hypothesising, you would need to do the following:

  1. Make the pipe sufficiently small that surface tension and adhesion (roughly the capillary effect) keep water from collecting at the bottom when the pipe is horizontal.

  2. Fill the pipe with air.

  3. Close off both ends of the pipe.

  4. Fill the containers to have the described water level with respect to the pipe end.

  5. Open the pipe ends.

Now, both ends of the pipe will have the same pressure and be in balance. The key difference here is that air is much lighter than water and thus the build-up of pressure along the inclined pipe is negligible.

Note that on account of the increased pressure (with respect to the room), some water will enter the pipe on both sides until the air is compressed accordingly, which can help to straighten out minor inaccuracies with respect to fill level. Still, preparing this experiment requires great accuracy.

Wrzlprmft
  • 6,242
7

Since the column height above pipe attachment is not same in both the bottles, the pressure at both ends should be different and water should still flow, which is not the case.

Following on from your statement, if you fully immerse a straw vertically in a glass of water you would expect the water to flow into the bottom of the of the straw and out of the straw, which in fact does not happen.

There is indeed a pressure difference across the ends of the straw but at each position within the straw the net force acting at that point is zero.
Going back to the vertical straw in the water, the higher pressure of the liquid at the bottom of the straw produces a higher upward force on the liquid within the straw that the downward force produced by the lower pressure at the top of the straw. Thus there is a net upward force on the body of water within the straw due to the pressure difference at the ends of the straw which is exactly equal in magnitude and oppose in direction to the gravitational force of attraction on that water due to the Earth - there is a static equilibrium situation.

And the net upward force on the body of water within the straw due to the pressure difference at the ends of the straw you might have heard by a different name - upthrust.

When I filled one bottle with water, at equilibrium, both the bottles had same height of water from ground.
This experimental result shows that your floor is level and variations on your device were used by ancient civilizations and even present day builders to try ensure foundations are level.

Farcher
  • 95,680
  • In a water level, you don't even need to bother with a second container - the level in the hose itself can be used. – Mark Ransom Jan 04 '23 at 03:36
3

The scenario of two bottles connected by a straw, is the same as a single container with a straw in it in any orientation.

In short:
The water pressure at each point within the straw is in equilibrium.

In Long:
The reason water does not continue to travel up (or down) the straw after the water levels of both bottles are of equal height, is because the pressure at the lower end of the straw is balanced between the water depth in that bottle, and the water depth in the other bottle - not just the water in the straw . There is water above the high end of the straw in the other bottle - that water matters.

In other words, the straw essentially makes the two bottles a single container. And if, for example, you submerge a straw completely into just one container (bottle, tub, sink, or whatever), once filled with water, water does not continue to flow up the straw because the water pressure at each point within the straw is in equilibrium, just as the water at each point within the larger container is in equilibrium.

2

Thought experiment: Imagine removing one of the bottles and lifting the pipe above the water level in the remaining water bottle: Now there is certainly a pressure difference since one end is at air pressure and the other has the added effect of the water column.

Q: How high will the water rise in the pipe now?

A:

Only as high as the water level in the bottle (disregarding capillary action).

The pressure at both end of the pipe does not need to be the same for there to be an equilibrium. In fact, there is even a pressure difference between any two heights in each bottle but no net flow within the bottles. What matters is that energy is conserved.

To transport a water molecule from the lower end of the pipe to the higher end, we need energy which needs to come from somewhere. In the non-equilibrium situation it comes from the decrease in the height of the water level in the bottle, i.e. the potential energy of the water with respect to ground level.

In the case pictured, if water were transported from one bottle to the other we would be creating energy out of nowhere. You can imagine a water molecule, originally at water level in the bottle on the left, transported through random thermal motion along the pipe into the other bottle. It cannot rise higher than its original height without added energy.

  • Correction: A water molecule can rise higher than its original height as long as a different molecule falls down. The water molecules jitter around all over the place but on average they just swap places with each other and nothing really happens – user253751 Jan 02 '23 at 23:46
  • @user253751 True. This is why I chose a water molecule at water level. There are no water molecules at greater heights so moving this particular molecule to a higher level would require adding energy, as there exists no other molecule with which to swap places.

    It would have been better for me to use a small, yet macroscopic, volume of water in the example. With a single molecule it is still possible that, although water is almost incompressible, another molecule would move ever so slightly lower.

    – Miha Luntinen Jan 03 '23 at 06:42
  • it can obviously go down if the one below it goes up. – user253751 Jan 03 '23 at 07:08
  • @user253751 Yes. I'm not arguing with this. My original post was imprecise as it implicitly presumed other molecules stationary. Maybe it would be better to use a small, yet macroscopic, volume of water instead? If such a small volume were to rise above its original height, we would need an equivalent volume of molecules to go down in the fluid (on average), which would have a negligible probability. – Miha Luntinen Jan 04 '23 at 06:30
  • I do not think one needs to look at energy at all. Just forces are sufficient. The pressure gradient is nonzero, but it is exactly balanced by the gravity acceleration $g$. We have the hydrostatic equilibrium and zero net acceleration. Also, molecules are tricky, have their own momentum and so on. It is much easier to just think about a continuum and continuum "particles". – Vladimir F Героям слава Jan 04 '23 at 13:22