I have read about Feynman path integral which leads to classical limit. It said that because $\hbar \rightarrow 0$ in classical view. The function of path integral $\int e^{\frac{1}{\hbar}f(x)} dx$ will have very large frequency and only path which $\frac{d f(x)}{dx} = 0$ will not be destructed. However, I cannot find mathematical proof. Could you help me derived it?
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