When we "cut" an ordinary path integral, we obtain a state in the position representation. That is, if we fix some initial position $x_i$, then the path integral $$\int_{x_i}^{x_f}Dx e^{-S}$$ is just a complex function of the final position $x_f$ - i.e. it's just a wavefunction $\psi(x_f)$.
The phase space path integral is given by $$\int DxDp e^{i\int(p\dot{q}-H)dt}.$$ Usually, this path integral is thought of as a function of the initial and final positions, which are fixed, whilst the initial and final momenta are not fixed: all values of $p_i$ and $p_f$ are integrated over. But one could instead choose to think of it as a function of both the final position and final momentum, giving us some function $f(x_f,p_f)$.
Clearly $f$ isn't a wavefunction, since it depends on too many variables. I'd like to know: is $f$ equal to some well-known function of $x$ and $p$ (e.g. the Wigner distribution)? And does it carry any physical meaning?
Note that a totally valid answer might be "no, $f$ doesn't appear in the literature, and as far as we know it has no physical meaning".