Suppose we have a variable $x$ and a probability density $\rho(x)$. The pushforward of this density under a bijective function $y = f(x)$ is given by \begin{equation*} \rho'(y) = \frac{\rho(f^{-1}(y))}{|Df(f^{-1}(y))|} \end{equation*} where $Df$ is the Jacobian of $f$. My question is: is there an analogous transformation law for the wavefunction?
As a start, immediately we can see that since $|\psi(x)|^2$ is a probability measure, the transformation law given above fixes the form of $|\psi'(y)|^2$ as $|\psi(f^{-1}(y))|^2|Df^{-1}(y)|$. However, this does not fix the form of the transformation law for the phase. Is there an obvious way to get the form of both the modulus transformation law and the phase transformation?